删除记录

Question

我有一个表 [user_logs] ，其中包含以下字段 [username]、[datetimelog]

示例数据

==============
user1   2011-06-28 08:49:01
user2   2011-06-28 08:59:38
user3   2011-06-28 09:04:31
user4   2011-06-28 10:00:15
user2   2011-06-28 10:28:54
user1   2011-06-29 08:31:22
user9   2011-06-29 08:32:32
user2   2011-06-29 10:13:53
user1   2011-06-29 13:11:15

我想知道如何创建 SQL 删除查询来删除除最后一个日志之外的所有用户日志，以便上面的示例将在之后生成以下内容删除查询

user1   2011-06-29 13:11:15
user2   2011-06-29 10:13:53
user3   2011-06-28 09:04:31
user4   2011-06-28 10:00:15
user9   2011-06-29 08:32:32

Answer 1

怎么样：

DELETE FROM 
    MY_TABLE M -- delete from the table
LEFT JOIN
    MY_TABLE M2 ON M.user = M2.user -- table needs to be joined TO ITSELF
WHERE
    NOT M.LOG_DATE = MAX( M2.LOG_DATE ) -- Anything which isn't MAX goes.

这可行吗？

Answer 2

DELETE FROM table a WHERE time != (SELECT MAX(time) FROM table b WHERE b.user=a.user);

这里删除一行，如果不是同一user_id组内的最长时间

Answer 3

DELETE from user_logs UL1, user_logs UL2
where UL1.username =UL2.datetimelog
and UL1.datetimelog < UL2.datetimelog

尝试一下