计算RGB使用强度
我正在制作 Gauroud 算法，当我计算边缘上的点强度时，我不知道如何处理它。我试图解决这个问题：
private int getPointRGB(double intensity)
{
float[] hsb=null;
double newCrRed;
double newCrGr;
double newCrBlue;
int nRGB;
//crRed, crGr, crBlue - primary components of edge RGB
newCrRed = intensity*crRed;
newCrGr = intensity*crGr;
newCrBlue = intensity*crBlue;
hsb = Color.RGBtoHSB((int)newCrRed, (int)newCrGr, (int)newCrBlue, null);
nRGB = Color.HSBtoRGB(hsb[0], hsb[1], hsb[2]);
return(nRGB);
}
我是对的吗？
I was making a Gauroud algorithm and when i had calculated point intensity on the edge I didn't know what to do with it. I tried to decide this problem like:
private int getPointRGB(double intensity)
{
float[] hsb=null;
double newCrRed;
double newCrGr;
double newCrBlue;
int nRGB;
//crRed, crGr, crBlue - primary components of edge RGB
newCrRed = intensity*crRed;
newCrGr = intensity*crGr;
newCrBlue = intensity*crBlue;
hsb = Color.RGBtoHSB((int)newCrRed, (int)newCrGr, (int)newCrBlue, null);
nRGB = Color.HSBtoRGB(hsb[0], hsb[1], hsb[2]);
return(nRGB);
}
am I right?
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如果没有一个默认颜色选择器令人满意，您可以创建自己的自定义选择器面板，如 如何使用颜色选择器：创建自定义选择器面板。例如，您可以实施 CIE 1976 色彩空间，如图 此处。
If none of the default color choosers are satisfactory, you can create your own custom chooser panel, as discussed in How to Use Color Choosers: Creating a Custom Chooser Panel. For example, you could implement the CIE 1976 color space, shown here.