将 NSString 与数组的 NSString 字段进行匹配

发布于 2024-11-17 02:39:40 字数 805 浏览 1 评论 0原文

我有一个名为 myObjectArray 的 NSMutableArray，其中包含名为 myObject 的 NSObjects 数组。 myObject 有两个字段（元素？），它们是 NSString 的。像这样：

@interface myObject : NSObject {
   NSString * string1;
   NSString * string2;
}

我有一个 NSMutableArray ，其中包含大约 50 个这样的对象，所有对象都具有不同的 string1 和 string2 。然后我有一个独立的 NSString 变量，称为 otherString；

有没有一种快速方法可以从 myObjectArray 访问其 string1 与 otherString 匹配的 myObject？

我应该说，这就是我所拥有的，但我想知道是否有更快的方法：

-(void) matchString: {

    NSString * testString = otherString;
    for(int i=0; i<[myObjectArray count];i++){
    myObject * tempobject = [myObjectArray objectAtIndex:i];
        NSString * tempString = tempobject.string1;
        if ([testString isEqualToString:tempString]) {
            // do whatever
        }

    }

}

原文

I have an NSMutableArray called myObjectArray which contains and array of NSObjects called myObject. myObject has two fields (elements?) which are NSString's. like this:

@interface myObject : NSObject {
   NSString * string1;
   NSString * string2;
}

I have an NSMutableArray which contains about 50 of these objects, all with different string1's and string2's. then I have and independent NSString variable, called otherString;

Is there a fast way to access the myObject from myObjectArray whose string1 matches otherString?

i should say, this is what i have, but i wonder if there is a faster way:

-(void) matchString: {

    NSString * testString = otherString;
    for(int i=0; i<[myObjectArray count];i++){
    myObject * tempobject = [myObjectArray objectAtIndex:i];
        NSString * tempString = tempobject.string1;
        if ([testString isEqualToString:tempString]) {
            // do whatever
        }

    }

}

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枕花眠 2024-11-24 02:39:40

有几种方法可以做到这一点，

使用谓词

NSPredicate * filterPredicate = [NSPredicate predicateWithFormat:@"string1 MATCHES[cd] %@", otherString];
NSArray * filteredArray = [myObjectArray filteredArrayUsingPredicate:filterPredicate];

现在filteredArray拥有所有具有string1的myObject实例> 匹配 otherString。

使用indexOfObjectPassingTest:

NSUInteger index = [myObjectArray indexOfObjectPassingTest:^(BOOL)(id obj, NSUInteger idx, BOOL *stop){
    myObject anObject = obj;
    return [anObject.string1 isEqualToString:otherString];
}

如果有满足条件的对象， index 会将您指向其索引。否则它将具有值NSNotFound。

如果您希望所有对象都满足条件，您还可以查看indexesOfObjectsPassingTest:。

There are a few ways you can do this,

Using Predicates

NSPredicate * filterPredicate = [NSPredicate predicateWithFormat:@"string1 MATCHES[cd] %@", otherString];
NSArray * filteredArray = [myObjectArray filteredArrayUsingPredicate:filterPredicate];

Now filteredArray has all the myObject instances that have their string1 matching otherString.

Using indexOfObjectPassingTest:

NSUInteger index = [myObjectArray indexOfObjectPassingTest:^(BOOL)(id obj, NSUInteger idx, BOOL *stop){
    myObject anObject = obj;
    return [anObject.string1 isEqualToString:otherString];
}

If there is an object that satisfies the condition, index will point you to its index. Otherwise it will have the value NSNotFound.

You can also look at indexesOfObjectsPassingTest: if you want all the objects satisfying the condition.

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