不想解雇 UIPopover
我正在使用以下代码在我的 View 中显示一个弹出窗口，
imagePopOver = [[UIPopoverController alloc];
initWithContentViewController:self.photoLibraryImageCollection.imagePickerController];
imagePopOver.popoverContentSize = CGSizeMake(185,675);
imagePopOver.delegate = self;
[imagePopOver presentPopoverFromRect:CGRectMake(600,0, 140, 800)
inView:self.view
permittedArrowDirections:UIPopoverArrowDirectionLeft animated:YES];
它工作正常，但是如果我们单击 myView 的任何其他部分，则显示的弹出窗口将消失。任何人都可以告诉我如何避免此问题。我任何时候都不想解雇它。任何人都可以告诉我该怎么做吗？
i am using this following code to display a popover in my View
imagePopOver = [[UIPopoverController alloc];
initWithContentViewController:self.photoLibraryImageCollection.imagePickerController];
imagePopOver.popoverContentSize = CGSizeMake(185,675);
imagePopOver.delegate = self;
[imagePopOver presentPopoverFromRect:CGRectMake(600,0, 140, 800)
inView:self.view
permittedArrowDirections:UIPopoverArrowDirectionLeft animated:YES];
it working fine however if we click any other part of myView ,this displayed popover is dismissing.can any one tell me how can i avoid this problem. i don't want to dismiss it at any time.can any one tell me how can do it.
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在弹出窗口的委托（可能是您的 viewController）中，实现
不要忘记设置委托！
In the popover's delegate (your viewController, probably), implement
Don't forget to set the delegate!
只是在弹出窗口初始化时编写了以下代码。
上面代码中的myPopOver.passthroughViews = [NSArray arrayWithObject:self.view];
不会关闭您的 popOver，我们可以使用我们的视图。
如果您不想仅在编辑文本框时关闭 UIpopover，只需编写
myPopOver.passthroughViews = [NSArray arrayWithObject:self.textBox];
just wrote the below code at the time of popover initialization.
myPopOver.passthroughViews = [NSArray arrayWithObject:self.view];
in the above code will not dismiss your popOver and we can work with our View.
if you don't want to dismiss UIpopover only at the time of a textBox edit,simply write
myPopOver.passthroughViews = [NSArray arrayWithObject:self.textBox];