如何从代码中删除缩进？
让我们考虑这个代码示例...不要看代码，而要看缩进。
protected function _hashPassword( $password, $salt, $nuts = '' ) {
if ( $nuts === '' ) {
$nuts = Kohana::config( 'a11n' )->nuts;
}
$password =
sha1(
$password
. $salt
. $nuts
);
return $password;
}
它取自更大的源代码。正如您所看到的，它缩进了 2 个制表符。我想以某种方式在不使用打字的情况下删除缩进。不知何故。
如果我使用编辑器内置“替换”功能并删除这两个选项卡，例如...
我得到这样的东西（不是在所有情况下，但几乎）...
protected function _hashPassword( $password, $salt, $nuts = '' ) {
if ( $nuts === '' ) {
$nuts = Kohana::config( 'a11n' )->nuts;
}
$password =
sha1(
$password
. $salt
. $nuts
);
return $password;
}
这是因为一行上不止两个选项卡，它取代了所有 4 个选项卡。
我正在寻找足够强大的正则表达式来很好地删除缩进！也许还有其他解决方案吗？只是不建议编写没有缩进的代码！
Lets consider this example of code... Don't look at code, but at indents.
protected function _hashPassword( $password, $salt, $nuts = '' ) {
if ( $nuts === '' ) {
$nuts = Kohana::config( 'a11n' )->nuts;
}
$password =
sha1(
$password
. $salt
. $nuts
);
return $password;
}
It's taken from much bigger source code. As you can see, it's indented by 2 tabs. I want to somehow remove indent from it without using typing. Somehow.
If I use in-editor build-in 'Replace' function and remove those two tabs like...
I get something like this (not in all cases, but almost)...
protected function _hashPassword( $password, $salt, $nuts = '' ) {
if ( $nuts === '' ) {
$nuts = Kohana::config( 'a11n' )->nuts;
}
$password =
sha1(
$password
. $salt
. $nuts
);
return $password;
}
It's because there are more than only two tabs on one line and it replaces all 4 tabs.
I'm looking for regular expression that's powerful enough to remove indent nicely! Maybe there are any other solutions? Just don't suggest to write code without indents!
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在您最喜欢的现代编辑器中选择代码，然后按 Shift+Tab。
Select the code in your favorite modern editor, and hit Shift+Tab.
当然，您想简单地替换
^\t\t，或者使用编辑器具有的任何字符作为行首锚点，如果它不是^（我不知道您的特定编辑器的功能是什么，只是（相当好）了解大多数正则表达式引擎的驱动方式）。这只会替换每行开头的两个选项卡项目。
例如，如果我在 Linux 下从命令行执行此操作，
就会执行您想要的操作。
Surely you want to simply replace
^\t\t, or use whatever character your editor has for the start-of-line anchor if it's not^(I have no idea what the capabilities of your particular editor are, only a (pretty good) understanding of how most regular expression engines are driven).This will only replace two-tab items at the start of each line.
For example, if I were doing this from the command line under Linux,
would do what you desire.
使用正则表达式，将
^\t\t替换为空字符串。在不使用正则表达式的情况下，只需将
\n\t\t替换为\n即可。另请考虑使用源代码格式化程序。
Using regular expressions, replace
^\t\twith the empty string.Without using regular expressions, simply replace
\n\t\twith\n.Also consider using a source code formatter.
以下内容适用于 Notepad++：
1) 将搜索模式设置为：正则表达式
2) 查找内容：
^[\t]+3) 替换为：
编辑：这将从头开始替换 1 个或多个选项卡每行。
替代方法：选择整个源代码并多次点击
Shift-Tab。它将删除每行开头的制表符，就像上面的正则表达式一样。我希望这有帮助！The following applies to Notepad++:
1) Set search mode to: Regular expression
2) Find what:
^[\t]+3) Replace with:
Edit: This will replace 1 or more tabs from the beginning of every line.
Alternative method: select the whole source code and hit
Shift-Tabmultiple times. It will remove the tabs from the beginning of every line, just like the regex above. I hope this helps!