创建 WPFon showdialog 事件
创建一个新窗口弹出窗口,
PopupWindows.PaymentsSummary paymentsSummary = new PopupWindows.PaymentsSummary
paymentsSummary.ParentWindow = Window.GetWindow(this);
paymentsSummary.ShowDialog();
我正在使用“付款摘要”窗口中的加载函数
private void Window_Loaded(object sender, RoutedEventArgs e)
{
basepage.payments.BindPaymentSummaryToDataGrid(uiActiveItems, basepage.user.terminal.TerminalId, true);
basepage.payments.BindPaymentSummaryToDataGrid(uiInActiveItems, basepage.user.terminal.TerminalId, false);
}
该函数的功能是
public void BindPaymentSummaryToDataGrid(DataGrid dgrid, int terminalId, bool isActivePayment)
{
BLPinNumber pins = new BLPinNumber();
string pinNumber = String.Empty;
long pinId = pins.getPinId(terminalId, ref pinNumber);
using (var dbEntities = new DatabaseAccess.Schema.Entities())
{
dgrid.DataContext = dbEntities.getPaymentRecordsByPinId((int)pinId, isActivePayment);
}
}
上面的代码调用 SQL Server 中的存储过程并返回一个对象,
但是当应用程序运行时,单击在以下行中显示弹出窗口 paymentSummary.ShowDialog();
The ObjectContext instance has been disposed and can no longer be used for operations that require a connection.
我已经在数据网格的 XAML 中将其归结为以下代码,
DataGrid ItemsSource="{Binding}" Grid.Column="{Binding}"
如果我删除此代码,它可以工作,但数据不会明显加载。
所以我相信我需要做的是绑定 datagrid onShowDialog 方法。
我如何创建这个?
或者有没有更好的方法使用实体框架来做到这一点,我习惯了 ASP.NET,在 ASP.NET 中,使用 DATAGRIDS 似乎更容易,尽管功能稍弱一些。
非常感谢
I am creating a new window popup window using
PopupWindows.PaymentsSummary paymentsSummary = new PopupWindows.PaymentsSummary
paymentsSummary.ParentWindow = Window.GetWindow(this);
paymentsSummary.ShowDialog();
on my load function in the Payment summary window I have
private void Window_Loaded(object sender, RoutedEventArgs e)
{
basepage.payments.BindPaymentSummaryToDataGrid(uiActiveItems, basepage.user.terminal.TerminalId, true);
basepage.payments.BindPaymentSummaryToDataGrid(uiInActiveItems, basepage.user.terminal.TerminalId, false);
}
The function is
public void BindPaymentSummaryToDataGrid(DataGrid dgrid, int terminalId, bool isActivePayment)
{
BLPinNumber pins = new BLPinNumber();
string pinNumber = String.Empty;
long pinId = pins.getPinId(terminalId, ref pinNumber);
using (var dbEntities = new DatabaseAccess.Schema.Entities())
{
dgrid.DataContext = dbEntities.getPaymentRecordsByPinId((int)pinId, isActivePayment);
}
}
The above code calls a Stored Proc in SQL Server and returns an object,
However when the app runs I get the error when clicking to show the popup on the following line paymentsSummary.ShowDialog();
The ObjectContext instance has been disposed and can no longer be used for operations that require a connection.
I have worked that down to the following code in the XAML for the datagrid
DataGrid ItemsSource="{Binding}" Grid.Column="{Binding}"
If i remove this code it works but the data doesnt load obvioulsy.
So what I believe I need to do is bind the datagrid onShowDialog method.
How do i create this ?
Or is there a better way of doing this using the Entity framework, im used to ASP.NET where working with DATAGRIDS seem easier, if ablight less powerful.
Many thanks
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您的问题是延迟加载!,您有 2 个选项:
Your problem is lazy loading!, you got 2 options: