如何在Android中使用RPC以json格式从服务器（PHP）获取数据

发布于 2024-11-16 09:20:17 字数 989 浏览 1 评论 0原文

我是安卓新手。我正在尝试创建一个 RPC 来从 PHP 获取数据并获取 JSON 格式。一切顺利，但我没有收到任何数据作为响应。下面是我的 android 代码

Android 代码

try{
    HttpClient httpClient = new DefaultHttpClient();


    JSONObject jsonRequest = new JSONObject(); 
    jsonRequest.put("id", 0); 
    jsonRequest.put("method", "getData"); 


    HttpEntity entity = new StringEntity(jsonRequest.toString()); 
    HttpPost request = new HttpPost("http://121.247.130.30:8080/test/TestJava.php");
    request.setEntity(entity); 
    HttpResponse response = httpClient.execute(request); 
    String temp = EntityUtils.toString(response.getEntity());
    Log.e("Class====","Error:"+temp);
   }
   catch(Exception e){
       Log.e("Class====","Error:"+e.getMessage());
   }

PHP 代码

<?php
class TestJava
{
public function getData()  
{  
   $arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
   echo json_encode($arr);
} 
}
?>

如果我在这里做了什么，请告诉我

原文

I am new in Android. I am trying to make an RPC to fetch data from PHP and get in JSON format. Everything goes fine but I am not getting any data as response. Bellow is my android code

Android Code

try{
    HttpClient httpClient = new DefaultHttpClient();


    JSONObject jsonRequest = new JSONObject(); 
    jsonRequest.put("id", 0); 
    jsonRequest.put("method", "getData"); 


    HttpEntity entity = new StringEntity(jsonRequest.toString()); 
    HttpPost request = new HttpPost("http://121.247.130.30:8080/test/TestJava.php");
    request.setEntity(entity); 
    HttpResponse response = httpClient.execute(request); 
    String temp = EntityUtils.toString(response.getEntity());
    Log.e("Class====","Error:"+temp);
   }
   catch(Exception e){
       Log.e("Class====","Error:"+e.getMessage());
   }

PHP Code

<?php
class TestJava
{
public function getData()  
{  
   $arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
   echo json_encode($arr);
} 
}
?>

Please let me know if anything I did here

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

故乡的云 2024-11-23 09:20:17

我认为您滥用了实体元素。检查我的代码中有什么：

StatusLine statusLine = response.getStatusLine();

if(statusLine.getStatusCode() == HttpStatus.SC_OK ){

    ByteArrayOutputStream out = new ByteArrayOutputStream();
    response.getEntity().writeTo(out);
    response.getEntity().consumeContent();
    out.close();
    return out.toString();

}

I think you misused entity element. Check what I have in my code:

StatusLine statusLine = response.getStatusLine();

if(statusLine.getStatusCode() == HttpStatus.SC_OK ){

    ByteArrayOutputStream out = new ByteArrayOutputStream();
    response.getEntity().writeTo(out);
    response.getEntity().consumeContent();
    out.close();
    return out.toString();

}

回复收藏 0 原文

慕烟庭风 2024-11-23 09:20:17

我有点惊讶你如何从这个 php 脚本中检索任何信息。该脚本不输出任何内容。尝试这样：

<?php
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
echo json_encode($arr);
?>

第二个“奇怪”的事情是您在应用程序中接收数据的方式。你应该读取输入流而不是写入输出流......或者我完全错过了什么？！

I am a little surprised how you could retrieve any information from this php script. This script doesnt output anything. Try it like this:

<?php
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
echo json_encode($arr);
?>

The second "strange" thing is your way of receiving data in your app. You should read a input stream instead of writing into a output stream... Or did I completely miss something?!

回复收藏 0 原文

~没有更多了~