如何在 MFC 中启动对话框？
我对 VC++ 和 MFC 还很陌生，所以请耐心等待。我创建了一个新对话框，我想弄清楚当用户单击按钮时如何显示它。
我还没有为对话框创建类或头文件——我尝试使用类向导，但它非常糟糕并且不起作用。那，或者我做错了什么。如果你问我的话，其中任何一种可能性都一样。
那么，在创建源文件/头文件并启动/显示对话框时，我需要采取哪些步骤？这是一个模式对话框。
澄清：我知道我需要创建对话框类的实例，然后只需在其上调用 DoModal() ，但我不确定如何创建类文件（带和/或不带向导）。
I'm fairly new to VC++ and MFC, so bear with me. I have created a new dialog, and I want to figure out how to display it when the user clicks a button.
I have not create a class or header file for the dialog -- I tried using the class wizard, but it pretty much sucked and didn't work. That, or I was doing something wrong. Either one is equally as likely if you ask me.
So what steps do I need to take when creating the source/header files and getting the dialog to launch/display? It is a modal dialog.
CLARIFICATION: I understand that I need to create an instance of the dialog class, then just call DoModal() on it, but I'm not sure how to create the class file (with and/or without the wizard).
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添加|资源...
键入并单击新建。
CMyDialog名称，基类的
CDialog并单击“完成”。
了解更多：如何制作 MFC 对话框
Add | Resource...
type and click New.
CMyDialogfor the Classname,
CDialogfor the Base classand Click Finish.
Read more: How to Make MFC Dialog Boxes
在我看来，您可以单击按钮，只需创建对话框对象的新实例并激活它。您可能必须保留对对话框的引用，以便当按钮操作 fxn 返回时它不会被杀死，它不会被垃圾收集。
Seems to me you can make the button click just create a new instance of the dialog object and activate it. You'll probably have to keep a reference to the dialog so it doesn't get killed when the button action fxn returns it doesn't get garbage collected..