如何将 NSString 的每个字符添加到 NSArray 中？

发布于 2024-11-16 06:33:19 字数 1099 浏览 4 评论 0原文

我正在寻找一种传递 NSString 的方法，它包含 4 个字符，整体代表一个 4 位数字，如 0741，我一直在四处寻找并不断遇到这个函数

myArray = [dataString componentsSeparatedByString:@"\r\n"];

ComponentsSeparatedByString...如果我的组件不是，我该怎么办分开了？

好吧，在查看下面发布的链接后，我发现了 NSRange，并设法让它与下面的解决方案完美配合，但是感觉有点冗长，而且可能比需要的更笨重......让我知道你是什么思考以及我可以做出哪些改进。

NSRange MyOneRange = {0, 1};
    NSRange MyTwoRange = {1, 1};
    NSRange MyThreeRange = {2, 1};
    NSRange MyFourRange = {3, 1};

    NSString *firstCharacter = [[NSString alloc] init];
    NSString *secondCharacter = [[NSString alloc] init];
    NSString *thridCharacter = [[NSString alloc] init];
    NSString *fourthCharacter = [[NSString alloc] init];

    firstCharacter = [myFormattedString substringWithRange:MyOneRange];
    secondCharacter = [myFormattedString substringWithRange:MyTwoRange];
    thridCharacter = [myFormattedString substringWithRange:MyThreeRange];
    fourthCharacter = [myFormattedString substringWithRange:MyFourRange];


    NSLog(@"%@, %@, %@, %@", firstCharacter, secondCharacter, thridCharacter, fourthCharacter);

原文

I am looking for a way to pass a NSString, which contains 4 charcters that in whole represent a 4 digit number like 0741, I have been looking around and keep coming across this function

myArray = [dataString componentsSeparatedByString:@"\r\n"];

componentsSeparatedByString... what can I do if my components are not separated?

Well, after checking out the link posted below I found NSRange, and have managed to get it working perfectly with this solution below, however it feels abit drawn out and maybe abit more bulky than it needs to be... let me know what you think and what improvements I could make.

NSRange MyOneRange = {0, 1};
    NSRange MyTwoRange = {1, 1};
    NSRange MyThreeRange = {2, 1};
    NSRange MyFourRange = {3, 1};

    NSString *firstCharacter = [[NSString alloc] init];
    NSString *secondCharacter = [[NSString alloc] init];
    NSString *thridCharacter = [[NSString alloc] init];
    NSString *fourthCharacter = [[NSString alloc] init];

    firstCharacter = [myFormattedString substringWithRange:MyOneRange];
    secondCharacter = [myFormattedString substringWithRange:MyTwoRange];
    thridCharacter = [myFormattedString substringWithRange:MyThreeRange];
    fourthCharacter = [myFormattedString substringWithRange:MyFourRange];


    NSLog(@"%@, %@, %@, %@", firstCharacter, secondCharacter, thridCharacter, fourthCharacter);

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狼亦尘 2024-11-23 06:33:19

为了即兴发挥你的方法，

NSRange theRange = {0, 1};
NSMutableArray * array = [NSMutableArray array];
for ( NSInteger i = 0; i < [myFormattedString length]; i++) {
    theRange.location = i;
    [array addObject:[myFormattedString substringWithRange:theRange]];
}

To improvise on your approach,

NSRange theRange = {0, 1};
NSMutableArray * array = [NSMutableArray array];
for ( NSInteger i = 0; i < [myFormattedString length]; i++) {
    theRange.location = i;
    [array addObject:[myFormattedString substringWithRange:theRange]];
}

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挖鼻大婶 2024-11-23 06:33:19

你有很多选择......有 - (unichar)characterAtIndex 方法启动。我建议阅读 NSString 文档（有一个名为“获取字符和字节”的方法部分）。

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遗忘曾经 2024-11-23 06:33:19

像这样的东西应该可以很好地工作：

NSString *dataString = @"0741";
NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[dataString length]];
for (int i = 0; i < [dataString length]; i++) {
    NSString *singleCharacter  = [NSString stringWithFormat:@"%c", [dataString characterAtIndex:i]];
    [characters addObject:singleCharacter];
}

Something like this should work nicely:

NSString *dataString = @"0741";
NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[dataString length]];
for (int i = 0; i < [dataString length]; i++) {
    NSString *singleCharacter  = [NSString stringWithFormat:@"%c", [dataString characterAtIndex:i]];
    [characters addObject:singleCharacter];
}

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