带汇总的 group by 子句

发布于 2024-11-16 05:16:23 字数 2293 浏览 4 评论 0原文

我尝试在 sql server 2005 中使用带有汇总子句的 group by 但遇到一些问题。

这是一个简单的转储

create table group_roll (
id int identity,
id_name int,
fname varchar(50),
surname varchar(50),
qty int
)

go
insert into group_roll (id_name,fname,surname,qty) values (1,'john','smith',10)
insert into group_roll (id_name,fname,surname,qty) values (1,'john','smith',30)
insert into group_roll (id_name,fname,surname,qty) values (2,'frank','white',5)
insert into group_roll (id_name,fname,surname,qty) values (1,'john','smith',8)
insert into group_roll (id_name,fname,surname,qty) values (2,'frank','white',10)
insert into group_roll (id_name,fname,surname,qty) values (3,'rick','black',10)
go

如果我运行这个简单的查询

select id_name,fname,surname,sum(qty) as tot
from group_roll
group by id_name,fname,surname

,我得到

1   john    smith   48
2   frank   white   15
3   rick    black   10

我想要的

1   john    smith   48
2   frank   white   15
3   rick    black   10
Total                73

这是我试图达到我的目标,

select 
case when grouping(id_name) = 1 then 'My total' else cast(id_name as char) end as Name_id ,
fname,surname,sum(qty) as tot
from group_roll
group by id_name,fname,surname
with rollup
order by case when id_name is null then 1 else 0 end, tot desc

但我的结果是

1                               john    smith   48
1                               john    NULL    48
1                               NULL    NULL    48
2                               frank   white   15
2                               frank   NULL    15
2                               NULL    NULL    15
3                               rick    black   10
3                               rick    NULL    10
3                               NULL    NULL    10
My total                         NULL   NULL   73

我的错误在哪里?

编辑。 我可以解决我的问题

select * from (
select cast(id_name as char) as id_name,fname,surname,sum(qty) as tot
from group_roll
group by id_name,fname,surname 
union
select 'Total',null,null,sum(qty) from group_roll ) as t
order by case when id_name = 'Total' then 1 else 0 end,tot desc

,但我想了解汇总是否可以解决我的问题。

I'm trying to use group by with rollup clause within sql server 2005 but I'm having some problem.

This is a simple dump

create table group_roll (
id int identity,
id_name int,
fname varchar(50),
surname varchar(50),
qty int
)

go
insert into group_roll (id_name,fname,surname,qty) values (1,'john','smith',10)
insert into group_roll (id_name,fname,surname,qty) values (1,'john','smith',30)
insert into group_roll (id_name,fname,surname,qty) values (2,'frank','white',5)
insert into group_roll (id_name,fname,surname,qty) values (1,'john','smith',8)
insert into group_roll (id_name,fname,surname,qty) values (2,'frank','white',10)
insert into group_roll (id_name,fname,surname,qty) values (3,'rick','black',10)
go

If I run this simple query

select id_name,fname,surname,sum(qty) as tot
from group_roll
group by id_name,fname,surname

I get

1   john    smith   48
2   frank   white   15
3   rick    black   10

I'd like to have

1   john    smith   48
2   frank   white   15
3   rick    black   10
Total                73

This is what I've tried to reach my goal

select 
case when grouping(id_name) = 1 then 'My total' else cast(id_name as char) end as Name_id ,
fname,surname,sum(qty) as tot
from group_roll
group by id_name,fname,surname
with rollup
order by case when id_name is null then 1 else 0 end, tot desc

but my result is

1                               john    smith   48
1                               john    NULL    48
1                               NULL    NULL    48
2                               frank   white   15
2                               frank   NULL    15
2                               NULL    NULL    15
3                               rick    black   10
3                               rick    NULL    10
3                               NULL    NULL    10
My total                         NULL   NULL   73

Where is my mistake?

EDIT.
I could solve my problem making

select * from (
select cast(id_name as char) as id_name,fname,surname,sum(qty) as tot
from group_roll
group by id_name,fname,surname 
union
select 'Total',null,null,sum(qty) from group_roll ) as t
order by case when id_name = 'Total' then 1 else 0 end,tot desc

but I'd like to understand if rollup can solve my problem.

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吃→可爱长大的 2024-11-23 05:16:23

您无法在语句本身中执行此操作,但是您可以过滤 ROLLUP 集,排除中间汇总,即对任何一行但不是所有行进行分组:

select
    case when grouping(id_name) = 1 then 'My total' else cast(id_name as char) end as Name_id,
    fname,
    surname,
    sum(qty) as tot
from group_roll
group by id_name, fname, surname
with rollup
having grouping(id_name) + grouping(fname) + grouping(surname) in (0 , 3)

或者与您的解决方案类似,但引用原始查询;

;with T as (
    select cast(id_name as varchar(128)) as id_name,fname,surname,sum(qty) as tot
    from group_roll
    group by id_name,fname,surname
) select * from T union all select 'Total:',null,null, SUM(tot) from T

FWIW SQL 2008 允许;

select
    case when grouping(id_name) = 1 then 'My total' else cast(id_name as char) end as Name_id,
    fname,
    surname,
    sum(qty) as tot
from group_roll
group by grouping sets((id_name, fname, surname), ())

You cannot do it within the statement itself, however you can filter the ROLLUP set excluding the intermediate rollups, i.e. where any one but not all rows are being grouped:

select
    case when grouping(id_name) = 1 then 'My total' else cast(id_name as char) end as Name_id,
    fname,
    surname,
    sum(qty) as tot
from group_roll
group by id_name, fname, surname
with rollup
having grouping(id_name) + grouping(fname) + grouping(surname) in (0 , 3)

Or similar to your solution but referencing the original query;

;with T as (
    select cast(id_name as varchar(128)) as id_name,fname,surname,sum(qty) as tot
    from group_roll
    group by id_name,fname,surname
) select * from T union all select 'Total:',null,null, SUM(tot) from T

FWIW SQL 2008 allows;

select
    case when grouping(id_name) = 1 then 'My total' else cast(id_name as char) end as Name_id,
    fname,
    surname,
    sum(qty) as tot
from group_roll
group by grouping sets((id_name, fname, surname), ())
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