Django tagging-tags 如何获取顶部标签的查询集？

发布于 2024-11-16 04:00:34 字数 1497 浏览 6 评论 0原文

我想为一个类编写一个管理器函数，该函数返回模型的关联标签并为每个标签分配一个计数值。

例如：

#models.py
class Snippet(models.Model):
    ...
    tags = TagField()
    objects = managers.SnippetManager()

-------------

#managers.py:
from tagging.models import Tag

class SnippetManager(models.Manager):
    def top_tags(self, klass):
        tag_list = Tag.objects.usage_for_model(klass, counts=True)
return ???

--------------

#views.py:
from django.views.generic.list_detail import object_list
from calloway.models import Snippet

def top_tags(request):
    return object_list(request, queryset=Snippet.objects.top_tags(Snippet),
                       template_name='calloway/top_tags.html',
                       paginate_by=20)

我希望 top_tags 管理器返回按附加属性排序的查询集，以便我可以循环遍历 object_list 并选出计数值。

即我的模板如下所示：

{% comment %} top_tags.html {% endcomment %}
{% for thistag in object_list %}
    <h2>Tag: {{ thistag.name }}</h2>
    <p>Count: {{ thistag.count }}</p>
    <p>Snippets:</p>
    {% tagged_objects thistag in calloway.Snippet as tagged_snippets %}
    {% for tagged_snippet in tagged_snippets %}
        <p><a href="{{ tagged_snippet.get_absolute_url }}">{{ tagged_snippet.title }}</a></p>
    {% endfor %}
{% endfor %}

任何人都可以推荐一种方法来执行此操作吗？如何将计数绑定到标签？ “注释”是解决方案吗？

对于那些感兴趣的人，我正在尝试完成实用 Django 项目第 8 章的“展望未来”段落中的“挑战”。

原文

I want to write a manager function for a class that returns the associated tags for a model and assigns a count value to each tag.

For example:

#models.py
class Snippet(models.Model):
    ...
    tags = TagField()
    objects = managers.SnippetManager()

-------------

#managers.py:
from tagging.models import Tag

class SnippetManager(models.Manager):
    def top_tags(self, klass):
        tag_list = Tag.objects.usage_for_model(klass, counts=True)
return ???

--------------

#views.py:
from django.views.generic.list_detail import object_list
from calloway.models import Snippet

def top_tags(request):
    return object_list(request, queryset=Snippet.objects.top_tags(Snippet),
                       template_name='calloway/top_tags.html',
                       paginate_by=20)

I'd like the top_tags manager to return a queryset ordered by an appended attribute, so that I can loop over the object_list and pick out the count value.

Ie my template looks like:

{% comment %} top_tags.html {% endcomment %}
{% for thistag in object_list %}
    <h2>Tag: {{ thistag.name }}</h2>
    <p>Count: {{ thistag.count }}</p>
    <p>Snippets:</p>
    {% tagged_objects thistag in calloway.Snippet as tagged_snippets %}
    {% for tagged_snippet in tagged_snippets %}
        <p><a href="{{ tagged_snippet.get_absolute_url }}">{{ tagged_snippet.title }}</a></p>
    {% endfor %}
{% endfor %}

Can anyone recommend a way to do this? How can I bind the count to the tag? Is "annotate" the solution?

For those interested I'm trying to complete the "challenge" in the "Looking Ahead" paragraph of Practical Django Projects, Chapter 8.

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迷爱 2024-11-23 04:00:34

所以这是我发现的一种方法。

基本上我完全忽略视图数据并使用 tagging-tags 模板标签直接访问模型内容。

如此

#managers.py
class SnippetManager(models.Manager):
def top_tags(self, klass):
    return Tag.objects.all()

然后……

{% comment %} top_tags.html {% endcomment %}
{% load tagging_tags %}

<html>
    <head>
        <title>Top Tags</title>
</head>
<body>
    {% tags_for_model calloway.Snippet as snippet_tags with counts %}
    {% regroup snippet_tags|dictsort:"count" by count as regrouped_snippet_tags %}
    {% for group in regrouped_snippet_tags reversed %}
        {% for thistag in group.list %}
            <h2>Tag: {{ thistag.name }}</h2>
            <p>Count: {{ group.grouper }}</p>
            <p>Snippets:</p>
            {% tagged_objects thistag in calloway.Snippet as tagged_snippets %}
            {% for tagged_snippet in tagged_snippets %}
                <p><a href="{{ tagged_snippet.get_absolute_url }}">{{ tagged_snippet.title }}</a></p>
            {% endfor %}
        {% endfor %}
    {% endfor %}
</body>
</html>

尽管最终结果是我想要的，但这似乎是一种笨拙的做法。

有没有办法通过管理器和视图来做到这一点？我认为这就是这次演习的目的。

So here's a way I've found to do it.

Basically I'm ignoring the view data completely and using the tagging-tags template tags to directly access the model contents.

#managers.py
class SnippetManager(models.Manager):
def top_tags(self, klass):
    return Tag.objects.all()

and then...

{% comment %} top_tags.html {% endcomment %}
{% load tagging_tags %}

<html>
    <head>
        <title>Top Tags</title>
</head>
<body>
    {% tags_for_model calloway.Snippet as snippet_tags with counts %}
    {% regroup snippet_tags|dictsort:"count" by count as regrouped_snippet_tags %}
    {% for group in regrouped_snippet_tags reversed %}
        {% for thistag in group.list %}
            <h2>Tag: {{ thistag.name }}</h2>
            <p>Count: {{ group.grouper }}</p>
            <p>Snippets:</p>
            {% tagged_objects thistag in calloway.Snippet as tagged_snippets %}
            {% for tagged_snippet in tagged_snippets %}
                <p><a href="{{ tagged_snippet.get_absolute_url }}">{{ tagged_snippet.title }}</a></p>
            {% endfor %}
        {% endfor %}
    {% endfor %}
</body>
</html>

This seems like a cludgy way of doing it though, although the end result is what I want.

Is there a way to do it through the manager and view? I think that's what the exercise is intended to produce.

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