在文本框中的树视图中显示 XML 架构数据

Question

我是这个项目的新手。它是在 Visual Studio 2010 上用 C# 编写的。我试图在带有树视图的文本框中显示此 XML 架构。我在将其变成树视图时遇到问题。

 数据集 dsM= new DataSet("M");
            string filePath = @"C:\Documents and Settings\Administrator\Desktop\M.xsd";
            dsM.ReadXml(文件路径);
            System.IO.StringWriter swXML = new System.IO.StringWriter();
            dsM.WriteXmlSchema(swXML);
            textBox.Text = swXML.ToString();

Answer 1

using System;
using System.Windows.Forms;
using System.Xml;

public class XmlTreeDisplay : System.Windows.Forms.Form{
    private System.Windows.Forms.TreeView treeXml = new TreeView();

    public XmlTreeDisplay() {
        treeXml.Nodes.Clear();
        this.Controls.Add(treeXml);
        // Load the XML Document
        XmlDocument doc = new XmlDocument();
        string filePath = @"C:\Documents and Settings\Administrator\Desktop\M.xsd";

        try {
            doc.Load(filePath);
        }catch (Exception err) {

            MessageBox.Show(err.Message);
            return;
        }

        ConvertXmlNodeToTreeNode(doc, treeXml.Nodes);
        treeXml.Nodes[0].ExpandAll();
    }

    private void ConvertXmlNodeToTreeNode(XmlNode xmlNode, 
      TreeNodeCollection treeNodes) {

        TreeNode newTreeNode = treeNodes.Add(xmlNode.Name);

        switch (xmlNode.NodeType) {
            case XmlNodeType.ProcessingInstruction:
            case XmlNodeType.XmlDeclaration:
                newTreeNode.Text = "<?" + xmlNode.Name + " " + 
                  xmlNode.Value + "?>";
                break;
            case XmlNodeType.Element:
                newTreeNode.Text = "<" + xmlNode.Name + ">";
                break;
            case XmlNodeType.Attribute:
                newTreeNode.Text = "ATTRIBUTE: " + xmlNode.Name;
                break;
            case XmlNodeType.Text:
            case XmlNodeType.CDATA:
                newTreeNode.Text = xmlNode.Value;
                break;
            case XmlNodeType.Comment:
                newTreeNode.Text = "<!--" + xmlNode.Value + "-->";
                break;
        }

        if (xmlNode.Attributes != null) {
            foreach (XmlAttribute attribute in xmlNode.Attributes) {
                ConvertXmlNodeToTreeNode(attribute, newTreeNode.Nodes);
            }
        }
        foreach (XmlNode childNode in xmlNode.ChildNodes) {
            ConvertXmlNodeToTreeNode(childNode, newTreeNode.Nodes);
        }
    }
    public static void Main(){
       Application.Run(new XmlTreeDisplay());
    }
}

修改它以满足您的需求...

（要执行相反的操作，请将 TreeView 转换为 XML，这是一个很好的演示，无需在这里重复）