id 是 python 中的关键字吗？

Question

我的编辑器 (TextMate) 以与我常用的变量名称不同的颜色（用作变量名称时）显示 id。是关键字吗？我不想遮蔽任何关键字...

Answer 1

这是一个内置函数：

id(...)
    id(object) -> integer

    Return the identity of an object.  This is guaranteed to be unique among
    simultaneously existing objects.  (Hint: it's the object's memory address.)

Answer 2

id 不是 Python 中的关键字，但它是 内置函数。

关键字是：

and       del       from      not       while
as        elif      global    or        with
assert    else      if        pass      yield
break     except    import    print
class     exec      in        raise
continue  finally   is        return
def       for       lambda    try

关键字是无效的变量名称。以下内容将是语法错误：

if = 1

另一方面，诸如 id 或 type 或 str 之类的内置函数可以被隐藏：

str = "hello"    # don't do this

Answer 3

您还可以从 python 获得帮助：

>>> help(id)
Help on built-in function id in module __builtin__:

id(...)
    id(object) -> integer

    Return the identity of an object.  This is guaranteed to be unique among
    simultaneously existing objects.  (Hint: it's the object's memory address.)

或者您可以询问 IPython

IPython 0.10.2   [on Py 2.6.6]
[C:/]|1> id??
Type:           builtin_function_or_method
Base Class:     <type 'builtin_function_or_method'>
String Form:    <built-in function id>
Namespace:      Python builtin
Docstring [source file open failed]:
    id(object) -> integer

Return the identity of an object.  This is guaranteed to be unique among
simultaneously existing objects.  (Hint: it's the object's memory address.)

Answer 4

仅供参考：

检查Python中是否有关键字：

>>> import keyword  
>>> keyword.iskeyword('id')
False

检查所有关键字在Python中：

>>> keyword.kwlist
['and', 'as', 'assert', 'break', 'class', 'continue', 'def', 'del', 'elif',
 'else', 'except', 'exec', 'finally', 'for', 'from', 'global', 'if', 'import',
 'in', 'is', 'lambda', 'not', 'or', 'pass', 'print', 'raise', 'return', 'try',
 'while', 'with', 'yield']