我不明白为什么 string.size 返回它的作用

Question

long_string = <<EOS
It was the best of times,
It was the worst of times.
EOS

返回 53。为什么？空白算不算？即便如此。我们如何得到53？

这个怎么样？

     def test_flexible_quotes_can_handle_multiple_lines
    long_string = %{
It was the best of times,
It was the worst of times.
}
    assert_equal 54, long_string.size
  end

  def test_here_documents_can_also_handle_multiple_lines
    long_string = <<EOS
It was the best of times,
It was the worst of times.
EOS
    assert_equal 53, long_string.size
  end

是这种情况吗，因为 %{ case 将每个 /n 计为一个字符，并且认为第一行之前有一个，末尾有一个，然后在第二行末尾有一个，而在 EOS 的情况下，第一行之前只有一个，第一行之后只有一个？也就是说，为什么前者是54，后者是53呢？

Answer 1

对于：

long_string = <<EOS
It was the best of times,
It was the worst of times.
EOS

String is:
"It was the best of times,\nIt was the worst of times.\n"

It was the best of times, => 25
<newline> => 1
It was the worst of times. => 26
<newline> => 1
Total = 25 + 1 + 26 + 1 = 53

以及

long_string = %{
It was the best of times,
It was the worst of times.
}

String is:
"\nIt was the best of times,\nIt was the worst of times.\n"
#Note leading "\n"

如何工作：

在 < 的情况下，其后面的行是字符串的一部分。与 << 同一行的 << 之后以及到该行末尾的所有文本都将成为“标记”的一部分，用于确定何时字符串结束（在这种情况下，一行中的 EOS 本身与 < 匹配）。

对于 %{...}，它只是用来代替 "..." 的不同分隔符。因此，当字符串在 %{ 之后开始新行时，该换行符就是字符串的一部分。

尝试这个示例，您将看到 %{...} 的工作方式与 "..." 相同：

a = "
It was the best of times,
It was the worst of times.
"
a.length # => 54

b = "It was the best of times,
It was the worst of times.
"
b.length # => 53