如何获取给定 C++ 的 PyBindGen PyObject指针？
给定由 PyBindGen 创建的 PyObject，很容易获得指向包装的 C++ 对象的指针，只需在结构中使用 obj 成员即可：
typedef struct {
PyObject_HEAD
MyWrappedClass *obj;
PyObject *inst_dict;
PyBindGenWrapperFlags flags:8;
} PyMyWrappedClass;
但是，假设我只有 MyWrappedClass*，并且想要获取包装它的 PyObject （如果有，它可能不存在）。有没有办法在不维护我自己的反向指针字典的情况下做到这一点？
Given the PyObject created by PyBindGen, it's easy to get the pointer to the wrapped C++ object, just use the obj member in the struct:
typedef struct {
PyObject_HEAD
MyWrappedClass *obj;
PyObject *inst_dict;
PyBindGenWrapperFlags flags:8;
} PyMyWrappedClass;
However, let's say I have just MyWrappedClass*, and want to get the PyObject (if any, it might not exist) that wraps it. Is there any way to do this without maintaining my own dictionary of backpointers?
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如果我有足够的声誉，我会将其添加为评论，因为我不熟悉
PyBindGen，但除非inst_dict是反向指针的字典（正如名称所暗示的那样） ）我认为你运气不好（除非你想遍历Python堆来查看那里是否有你的类的实例）。I would have added this as a comment if I had enough reputation as I'm not familiar with
PyBindGen, but unlessinst_dictis a dictionary of backpointers (as the name might suggest) I think you're out of luck (Unless you want to trawl through the Python heap to see if there are any instances of your class there).