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我正在开发事件列表应用程序，应用程序从数据库获取事件，事件到达应用程序正确抛出webservice，但我的问题是在listview的适配器中绑定soap对象，我这样做了，
try {
aht.call(SOAP_ACTION, envelope);
resultsRequestSOAP = (SoapObject) envelope.getResponse();
// rs = (SoapPrimitive) envelope.getResponse();
// resultString = (List<UBAEvent>)envelope.getResponse();
} catch (Exception e) {
e.printStackTrace();
}
int x = resultsRequestSOAP.getPropertyCount();
adapter = new MyArrayAdapter(this);
UBAEvent ubaEvent = new UBAEvent();
for (int i = 0; i < x; i++) {
ubaEvent = (UBAEvent) resultsRequestSOAP.getProperty(i);
adapter.add(ubaEvent);
}
但它不是任何人都可以帮助我如何将肥皂对象绑定到适配器中吗？
i am working on application for events listing , the application get the events from the database , the events arrive to the application throw webservice correctly , but my problem is to bind the soap object in adapter of the listview , i do this
try {
aht.call(SOAP_ACTION, envelope);
resultsRequestSOAP = (SoapObject) envelope.getResponse();
// rs = (SoapPrimitive) envelope.getResponse();
// resultString = (List<UBAEvent>)envelope.getResponse();
} catch (Exception e) {
e.printStackTrace();
}
int x = resultsRequestSOAP.getPropertyCount();
adapter = new MyArrayAdapter(this);
UBAEvent ubaEvent = new UBAEvent();
for (int i = 0; i < x; i++) {
ubaEvent = (UBAEvent) resultsRequestSOAP.getProperty(i);
adapter.add(ubaEvent);
}
but it is not work can any one help me how to bind the soap object into adapter ?
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评论（1）
您首先需要解析在您的情况下soapobjects 中的答案是resultsRequestSOAP。如果启用调试，则在变量 at 中您将获得 XML 响应。该 xml 已在 resultsRequestSOAP 对象中进行解析。要回顾一下，您需要执行以下操作：
在这些之后，您构建对象 ubaEvent 您尝试复杂类型，所以我知道的最好方法是这些，或者您可以尝试序列化的困难方法
You first need to parse the answer ok that is in soapobjects in your case is resultsRequestSOAP. If you enable debug, in variable aht you have the XML response. And that xml is already parsed in resultsRequestSOAP object. To retreview you do these :
after these you build the object ubaEvent you trying complex types so best way i know is these one or you can try the hard way with serialization