Django - 服务媒体值错误

发布于 2024-11-15 03:59:15 字数 886 浏览 5 评论 0原文

我正在尝试在我的开发环境中提供用户上传的媒体文件。

#settings.py
#[...]
import os
SITE_ROOT = os.path.dirname(os.path.realpath(__file__))
MEDIA_ROOT = (os.path.join(SITE_ROOT, 'media/'))
MEDIA_URL = '/media/'
STATIC_URL = '/static/'
STATICFILES_DIRS = (
  os.path.join(SITE_ROOT, 'static/'),
)
#[...]

#url.py
urlpatterns = patterns('',
  #[...]
  url(r'^%s(?P<path>.*)$' % settings.MEDIA_URL[1:], 'django.views.static.serve',
    {'document_root', settings.MEDIA_ROOT}
  ),
  url(r'^%s(?P<path>.*)$' % settings.STATIC_URL[1:], 'django.views.static.serve',
    {'document_root', settings.STATIC_ROOT}
  ),
)

尝试访问上传的文件，例如 http://127.0.0.1:8000/media/videos /julian_06.flv，我明白了

/media/videos/julian_06.flv 处的值错误
字典更新序列元素#0的长度为40；需要2个

原文

I'm trying to serve user uploaded media files in my dev environment.

#settings.py
#[...]
import os
SITE_ROOT = os.path.dirname(os.path.realpath(__file__))
MEDIA_ROOT = (os.path.join(SITE_ROOT, 'media/'))
MEDIA_URL = '/media/'
STATIC_URL = '/static/'
STATICFILES_DIRS = (
  os.path.join(SITE_ROOT, 'static/'),
)
#[...]

#url.py
urlpatterns = patterns('',
  #[...]
  url(r'^%s(?P<path>.*)
Trying to access an uploded file like http://127.0.0.1:8000/media/videos/julian_06.flv, I get

ValueError at /media/videos/julian_06.flv
dictionary update sequence element #0 has length 40; 2 is required

 % settings.MEDIA_URL[1:], 'django.views.static.serve',
    {'document_root', settings.MEDIA_ROOT}
  ),
  url(r'^%s(?P<path>.*)
Trying to access an uploded file like http://127.0.0.1:8000/media/videos/julian_06.flv, I get

ValueError at /media/videos/julian_06.flv
dictionary update sequence element #0 has length 40; 2 is required

 % settings.STATIC_URL[1:], 'django.views.static.serve',
    {'document_root', settings.STATIC_ROOT}
  ),
)

Trying to access an uploded file like http://127.0.0.1:8000/media/videos/julian_06.flv, I get

ValueError at /media/videos/julian_06.flv
dictionary update sequence element #0 has length 40; 2 is required

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似狗非友 2024-11-22 03:59:15

我建议尝试遵循的文档开发中的静态托管

if settings.DEBUG:
urlpatterns += patterns('django.contrib.staticfiles.views',
    url(r'^media/(?P<path>.*)
 编辑：

您的字典应该在 'document_root' 和 <代码>设置.MEDIA_ROOT
urlpatterns = patterns('',
url(r'^%s(?P<path>.*)
, 'serve'),
)

 编辑：

您的字典应该在 'document_root' 和 <代码>设置.MEDIA_ROOT

 % settings.MEDIA_URL[1:], 'django.views.static.serve',
    {'document_root': settings.MEDIA_ROOT}),
)

, 'serve'), )

编辑：

您的字典应该在 'document_root' 和 <代码>设置.MEDIA_ROOT

I'd recommend trying to follow the docs for static hosting in development

if settings.DEBUG:
urlpatterns += patterns('django.contrib.staticfiles.views',
    url(r'^media/(?P<path>.*)
EDIT:
Your dictionary should have a : not , between the 'document_root' and settings.MEDIA_ROOT
urlpatterns = patterns('',
url(r'^%s(?P<path>.*)
, 'serve'),
)

EDIT:
Your dictionary should have a : not , between the 'document_root' and settings.MEDIA_ROOT

 % settings.MEDIA_URL[1:], 'django.views.static.serve',
    {'document_root': settings.MEDIA_ROOT}),
)