我不太明白这个基本的java程序
由于我对java非常陌生，我似乎很难掌握一些概念。这是一个程序。我对 System.out 部分理解得相当好，但我很难理解输入的工作原理。
// IO Example:
import java.util.Scanner;
public class HelloAge {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("What's your name? ");
String name = in.nextLine();
System.out.print("In which year were you born? ");
Integer birthyear = in.nextInt();
Integer age = 2011 - birthyear;
System.out.println("Hello, " + name + "! Welcome to COMP1100.\n" +
"You will turn " + age + " this year.");
}
}
我不明白为什么有 in.nextLine(); 然后是 in.nextInt(); 我不明白这两个命令有什么共同点或什么他们应该是什么意思？这是我的主要问题。
As I'm extremely new to java, I seem to have trouble grasping some concepts. Here is a program. I understand the System.out part reasonably well but am having trouble getting my head around how the input works.
// IO Example:
import java.util.Scanner;
public class HelloAge {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("What's your name? ");
String name = in.nextLine();
System.out.print("In which year were you born? ");
Integer birthyear = in.nextInt();
Integer age = 2011 - birthyear;
System.out.println("Hello, " + name + "! Welcome to COMP1100.\n" +
"You will turn " + age + " this year.");
}
}
I can't see why there is in.nextLine(); and then in.nextInt(); I don't see what those two commands have in common or what they're supposed to mean? That's my main issue.
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（3）
一般来说，首先尝试 javadocs；在本例中为扫描仪文档。
首先创建一个新的扫描仪来读取标准输入...
读入整个下一行，其中是直到下一个换行符
的所有字符...将下一组字符读取为整数...
In general try the javadocs first; in this case the Scanner docs.
First create a new scanner for reading stdin...
Read in the entire next line which is all chars up to the next newline...
Read the next set of chars as an integer...
System.in 调用来自控制台的输入。然后扫描仪读取输入数据并将其转换为任何格式。 in.nextVar 是一个函数，它获取数据并读取一个“块”数据，并将其放入指定的格式。
System.in calls input from the console. The Scanner then reads that input data and puts it into whatever format. The in.nextVar is the function that takes the data and reads one 'chunk' of data, and puts it into the specified format.
您可以在扫描仪对象的本教程中找到答案。
You can may be find your answer in this tutorial on the scanner object.