Django：我应该使用查询字符串还是干净的 url 来映射显示参数？又如何呢？
我有以下 urlconf：
urlpatterns = patterns('page.manager.views',
url(r'^$', 'pages', name='page_manager-pages'),
url(r'^add/$', 'add_page', name='page_manager-add_page'),
url(r'^(?P<page_id>\d+)/', include(object_patterns)),
)
“页面”视图必须返回所有页面的对象列表。将通过侧面菜单向用户提供多个显示/搜索选项： - 创建：任意/过去 6 小时/12 小时/24 小时/周 - 状态：任意/status_1/status_2/status_3 - 持续时间：任意/duration_1/duration_2/duration_3 我
这些选项用于选择应向用户呈现哪些值并且可以组合使用，例如：created=any、status=status_1、duration=duration_1
的问题是，如何在 Django 中最好地实现这一点？
到目前为止我所拥有的： 我可以对列表对象的通用视图进行子类化，创建一个视图，该视图接受参数（创建、状态、持续时间等）并提供正确的查询集（使用与其他参数一起传递的所选[或默认]排序选项）。
为了传递这些参数，查询字符串似乎适合于此，因为我们是从资源（所有页面的列表）中进行选择。是/否？
我还知道我们从 request.GET.get('argument_name') 获取此信息。
但是如何创建搜索选项的链接呢？例如：任意、任意/status_1/status_2/status_3。我们需要知道哪些已经处于活动状态，所以...模板标签？也许有更简单的方法？
这是在 Django 中处理此类事情的正确解决方案，还是有更好的方法？
I have the following urlconf:
urlpatterns = patterns('page.manager.views',
url(r'^
The 'pages' view must return an object list of all pages. The user will be offered several display/search options through a side menu:
- created: any/ past 6hours/12hours/24hours/week
- Status: any/ status_1/status_2/status_3
- Duration: any / duration_1/duration_2/duration_3
etc.
These options are used to select which values should be presented to the user and can be used in combination, eg: created=any, status=status_1, duration=duration_1
My question is, how best to achieve this in Django?
What I have so far:
I can subclass a generic view for list objects, creating a view which takes the arguments(created, status, duration, etc) and provides the proper queryset(with the chosen[or default] ordering options passed along with the other arguments).
To pass these arguments, query strings seem to be right for this, since we are selecting from a resource(the list of all pages). Yes/no?
I'm also aware we get this information from request.GET.get('argument_name').
But how to create the links for the search options? eg: any, any/ status_1/status_2/status_3. We need to know which are already active, so...template tag? An easier way perhaps?
Is this the proper solution to handle this type of thing in Django, or is there a better way?
, 'pages', name='page_manager-pages'),
url(r'^add/
The 'pages' view must return an object list of all pages. The user will be offered several display/search options through a side menu:
- created: any/ past 6hours/12hours/24hours/week
- Status: any/ status_1/status_2/status_3
- Duration: any / duration_1/duration_2/duration_3
etc.
These options are used to select which values should be presented to the user and can be used in combination, eg: created=any, status=status_1, duration=duration_1
My question is, how best to achieve this in Django?
What I have so far:
I can subclass a generic view for list objects, creating a view which takes the arguments(created, status, duration, etc) and provides the proper queryset(with the chosen[or default] ordering options passed along with the other arguments).
To pass these arguments, query strings seem to be right for this, since we are selecting from a resource(the list of all pages). Yes/no?
I'm also aware we get this information from request.GET.get('argument_name').
But how to create the links for the search options? eg: any, any/ status_1/status_2/status_3. We need to know which are already active, so...template tag? An easier way perhaps?
Is this the proper solution to handle this type of thing in Django, or is there a better way?
, 'add_page', name='page_manager-add_page'),
url(r'^(?P<page_id>\d+)/', include(object_patterns)),
)
The 'pages' view must return an object list of all pages. The user will be offered several display/search options through a side menu:
- created: any/ past 6hours/12hours/24hours/week
- Status: any/ status_1/status_2/status_3
- Duration: any / duration_1/duration_2/duration_3
etc.
These options are used to select which values should be presented to the user and can be used in combination, eg: created=any, status=status_1, duration=duration_1
My question is, how best to achieve this in Django?
What I have so far:
I can subclass a generic view for list objects, creating a view which takes the arguments(created, status, duration, etc) and provides the proper queryset(with the chosen[or default] ordering options passed along with the other arguments).
To pass these arguments, query strings seem to be right for this, since we are selecting from a resource(the list of all pages). Yes/no?
I'm also aware we get this information from request.GET.get('argument_name').
But how to create the links for the search options? eg: any, any/ status_1/status_2/status_3. We need to know which are already active, so...template tag? An easier way perhaps?
Is this the proper solution to handle this type of thing in Django, or is there a better way?
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由于您有离散的、可选的和无序的知识片段有助于您的查询，因此我认为 GET 是最好的方法。另外，请注意 request.GET 是一个字典（因此，您可以执行 request.GET['status']）。
至于搜索选项，我想说模板标签和上下文变量可能合适，具体取决于您的视图的详细信息。我最可能的方法是用需要显示的 True / False 标志填充上下文字典，然后使用 {% if %} 块在模板中对其进行排序。
Since you have discrete, optional and unordered pieces of knowledge contributing to your query, I think that GET is the best way. Also, note that request.GET is a dict (ergo, you can do request.GET['status']).
As for the search options, I'd say a template tag and a context variable might either be appropriate depending on the details of your view. My most likely approach is to populate a context dict with True / False flags for which need to be displayed and then have {% if %} blocks to sort it out in the template.