ASP.NET - 将 UpdatePanel 触发器添加到 gridview 内的 LinkButton
我试图更新模式对话框的内容,此代码对我有用:
<asp:LinkButton ID="updateSomething" runat="server" Text="Update" CausesValidation="false" OnClientClick="openDialog();" onclick="UpdateButton_Click" />
<asp:UpdatePanel ID="upNewUpdatePanel" runat="server">
<ContentTemplate>
<asp:Label ID="updateLabel" runat="server"></asp:Label>
</ContentTemplate>
<Triggers>
<asp:AsyncPostBackTrigger ControlID="updateSomething" EventName="Click" />
</Triggers>
</asp:UpdatePanel>
但是,当我尝试将 LinkButton 放入 gridview 中时,如下所示:
<asp:GridView ID="grdListUsers" runat="server" AutoGenerateColumns="false" AllowPaging="false" OnRowDataBound="grdRowDefListUsers" CssClass="mGrid" EmptyDataText="No users.">
<Columns>
<asp:BoundField DataField="Name" HeaderText="Nome" HeaderStyle-Width="300" />
<asp:BoundField DataField="Login" HeaderText="Login" HeaderStyle-Width="300" />
<asp:TemplateField HeaderText="Options" HeaderStyle-Width="75" ItemStyle-HorizontalAlign="Center" ItemStyle-VerticalAlign="Middle">
<ItemTemplate>
<asp:LinkButton ID="updateSomething" runat="server" Text="Update" CausesValidation="false" OnClientClick="openDialog();" onclick="UpdateButton_Click" />
</asp:TemplateField>
</Columns>
</asp:GridView>
这不起作用,我收到一条错误消息:带有 ID 的控件在 UpdatePanel“upNewUpdatePanel”中找不到触发器“updateSomething”。
如何在 gridview 中使用 ImageButton?
I was trying to update the content of a modal dialog, and this code works for me:
<asp:LinkButton ID="updateSomething" runat="server" Text="Update" CausesValidation="false" OnClientClick="openDialog();" onclick="UpdateButton_Click" />
<asp:UpdatePanel ID="upNewUpdatePanel" runat="server">
<ContentTemplate>
<asp:Label ID="updateLabel" runat="server"></asp:Label>
</ContentTemplate>
<Triggers>
<asp:AsyncPostBackTrigger ControlID="updateSomething" EventName="Click" />
</Triggers>
</asp:UpdatePanel>
However, when I try to place the LinkButton inside a gridview, like so:
<asp:GridView ID="grdListUsers" runat="server" AutoGenerateColumns="false" AllowPaging="false" OnRowDataBound="grdRowDefListUsers" CssClass="mGrid" EmptyDataText="No users.">
<Columns>
<asp:BoundField DataField="Name" HeaderText="Nome" HeaderStyle-Width="300" />
<asp:BoundField DataField="Login" HeaderText="Login" HeaderStyle-Width="300" />
<asp:TemplateField HeaderText="Options" HeaderStyle-Width="75" ItemStyle-HorizontalAlign="Center" ItemStyle-VerticalAlign="Middle">
<ItemTemplate>
<asp:LinkButton ID="updateSomething" runat="server" Text="Update" CausesValidation="false" OnClientClick="openDialog();" onclick="UpdateButton_Click" />
</asp:TemplateField>
</Columns>
</asp:GridView>
This does not work, I get an error saying: A control with ID 'updateSomething' could not be found for the trigger in UpdatePanel 'upNewUpdatePanel'.
How can I use the ImageButton inside the gridview?
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尝试将
asp:AsyncPostBackTrigger
添加到asp:GridView
的OnRowCommand
事件,并处理该事件和 cs 中 的链接按钮单击像这样创建事件
Try and add the
asp:AsyncPostBackTrigger
to theasp:GridView
'sOnRowCommand
event and handle the link button click in that eventand in the cs create the event like this
您可以添加 gridview 的触发器
You could add a trigger of the gridview
在链接按钮周围添加另一个更新面板,如下所示。
Add another Update Panel surrounding your link button just like below.
您可以将 UpdatePanel 的 UpdateMode 设置为
Conditional
和 从 UpdateButton_Click-Handler 手动更新:LinkButton 的 Click-Event 处理程序:
You could set the UpdatePanel's UpdateMode to
Conditional
and update it manually from the UpdateButton_Click-Handler:LinkButton's Click-Event handler: