jquery grep json 对象数组

Question

我尝试使用 grep 过滤 json 对象数组，以便搜索该数组，如果键 #2-6 中任何一个的值为 yes，则返回键 1 和 7 的值。

该数组如下 - 换句话说，如果“位置”键的任何值为“是”，则名称和描述将作为列表项返回。

非常感谢任何帮助。

[
    {
        "name": "name",
        "location1": "no",
    "location2": "no",
    "location3": "yes",
    "location4": "no",
    "location5": "no",
    "description": "description of services"
    },

    {   
    "name": "name",
        "location1": "yes",
    "location2": "no",
    "location3": "yes",
    "location4": "no",
    "location5": "no",
    "description": "description of services"        
    }
]

Answer 1

您需要同时使用 grep 和 map。如果 a 是上述数组（但具有 name1、name2 等），则在以下内容之后：

var b = $.grep(a, function(el, i) {
    return el.location1.toLowerCase() === "yes" 
           || el.location2.toLowerCase() === "yes" 
           || el.location3.toLowerCase() === "yes" 
           || el.location4.toLowerCase() === "yes" 
           || el.location5.toLowerCase() === "yes";
});

var c = $.map(b, function(el, i) {
    return {
        name: el.name,
        description: el.description
    };
});

c 将包含 [{"name":"name1","description":"服务描述 1"},{"name":"name2","description":"服务描述 2"}]

<一href="http://jsfiddle.net/7zHP3/" rel="noreferrer">参见示例→

Answer 2

我的版本与之前的答案非常相似，希望对您有所帮助：

    var checkYes = function(element) {

        var isYesInside = false;

        $.each(element, function(key, value) {
            if (value == "yes")
                isYesInside = true;
        });

        return isYesInside;
    };

    var yeses = $.grep(a, function(element, index) {
        return checkYes(element);
    });

    var finalArray = $.map(yeses, function(el, i) {
        return {
            name: el.name,
            description: el.description
        };
    });