Android 中 USB 网络共享模式下 PC 的 IP 地址，无需 WIFI，以编程方式

发布于 2024-11-14 18:40:42 字数 668 浏览 3 评论 0原文

如何在不使用 WIFI 管理器的情况下以编程方式获取 Android 手机以 USB 网络共享模式连接的 PC 的 IP 地址、默认网关和端口号？

我使用了网络接口，但它没有给我正确的信息，还有其他方法吗？

for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
            NetworkInterface intf = en.nextElement();
            for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
                InetAddress inetAddress = enumIpAddr.nextElement();
                if (!inetAddress.isLoopbackAddress()) {
                    address += inetAddress.getHostAddress().toString() ;
                }
            }
        }

原文

How can I programatically get the Ip address, default gateway and port number of the PC to which the android phone is connected in USB Tethering mode, without using WIFI Manager?

I used network interfaces, but it doesnt give me the correct information, is there any other way?

for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
            NetworkInterface intf = en.nextElement();
            for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
                InetAddress inetAddress = enumIpAddr.nextElement();
                if (!inetAddress.isLoopbackAddress()) {
                    address += inetAddress.getHostAddress().toString() ;
                }
            }
        }

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记忆消瘦 2024-11-21 18:40:42

好的，这是我达到的圆形解决方案，从通过网络接口收到的地址中，我删除了地址中的最后一部分，例如 192.168.1.40，我删除了 40 并迭代从 192.168.1.0 开始的循环并找出实际连接的端口。片段如下

for(idx=0; idx <=255; idx++)
         {
             try
             {
                 t[idx] = new Thread(new Runnable() {
                        public void run() {
                            str = IPpart + "." + idx;
                                            socket = new Socket(str, PORT);
                                   IP = socket.getInetAddress().toString();
                             Gateway = socket.getLocalAddress().toString();
                        }
                    });
                 t[idx].setName("IPclass");
                 t[idx].start();
                 if(IP != "")
                 {
                     closeThread();
                     break;
                 }
             }catch(Exception ex){ }
         }

Ok here is the round about solution that I reached, from the address received through the network interface, I remove the last section in the address, like 192.168.1.40, i remove 40 and iterate through a loop starting from 192.168.1.0 and find out the port which actually connects. The snippet is below

for(idx=0; idx <=255; idx++)
         {
             try
             {
                 t[idx] = new Thread(new Runnable() {
                        public void run() {
                            str = IPpart + "." + idx;
                                            socket = new Socket(str, PORT);
                                   IP = socket.getInetAddress().toString();
                             Gateway = socket.getLocalAddress().toString();
                        }
                    });
                 t[idx].setName("IPclass");
                 t[idx].start();
                 if(IP != "")
                 {
                     closeThread();
                     break;
                 }
             }catch(Exception ex){ }
         }

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