如何在屏幕上显示 UIControl 的子类

Question

我通过以下代码创建了一个名为 ToggleImageControl 的 UIControl 子类（参考以下帖子 复选框图像在 UITableViewCell 中切换）

@interface ToggleImageControl : UIControl 
{
    BOOL photoIsStarred;
    UIImageView *imageView;
    UIImage *normalImage;
    UIImage *selectedImage;
}

@property (nonatomic, assign) BOOL photoIsStarred;
@property (nonatomic, retain) UIImageView *imageView;
@property (nonatomic, retain) UIImage *normalImage;
@property (nonatomic, retain) UIImage *selectedImage;

- (void) toggleImage;
@end


@implementation ToggleImageControl

@synthesize photoIsStarred, imageView, normalImage,selectedImage;

- (id)initWithFrame:(CGRect)frame 
{
    NSLog(@"in inti with frame method");
    self.normalImage = [UIImage imageNamed: @"blank_star.png"];
    self.selectedImage = [UIImage imageNamed: @"star.png"];
    self.imageView = [[UIImageView alloc] initWithImage: normalImage];

    // set imageView frame
    [self addSubview: imageView];

    [self addTarget: self action: @selector(toggleImage) forControlEvents: UIControlEventTouchDown];

return self;
}

- (void) toggleImage
{
    NSLog(@"image toggled");
    self.photoIsStarred = !photoIsStarred;
    self.imageView.image = (photoIsStarred ? selectedImage : normalImage); 
}

@end

我尝试在表格单元格中创建 ToggleImageControl 的实例，但无法显示“正常图像”。我的下面的实现中是否缺少某些内容？

//In a UItableview cell
ToggleImageControl *toggleControl = [[ToggleImageControl alloc]initWithFrame:CGRectMake(670, 10,80, 80)];

[cell.contentView addSubview:toggleControl];

Answer 1

确保在 initWithFrame: 方法中调用 [super initWithFrame:frame]。

前任

self = [super initWithFrame:frame];
if (self) {

  // Initialization

}

return self;