C# threadpool windows-services queueuserworkitem

Windows 服务未完全启动

发布于 2024-11-14 02:13:28 字数 1093 浏览 2 评论 0原文

我用 C# 创建了这个小型 Windows 服务，我相信我的 ThreadPool 代码可能做错了什么，导致 Windows 服务无法完全启动。如果您必须知道，Windows 服务似乎运行完美，只是当查看服务控制台时，它仍然表明它正在“启动”。当我重新启动服务器时，即使我已将其设置为自动启动，该服务似乎又停止了。

请参阅下面我的代码：

protected override void OnStart(string[] args)
{
     int itemCount = itemList.Count;

     this.doneEvents = new ManualResetEvent[itemCount];
     for (int i = 0; i < itemCount; i++)
     {
         int oId = this.itemList[i];
         this.doneEvents[i] = new ManualResetEvent(false);

         ThreadPool.QueueUserWorkItem(data =>
         {
             while (this.activated)
             {
                 DateTime start = DateTime.Now;

                 // my code here

                 // choke point
                 TimeSpan duration = (DateTime.Now - start);
                 if (duration.Milliseconds < CONST_WAITMILLISECONDS)
                    Thread.Sleep((CONST_WAITMILLISECONDS - duration.Milliseconds));
              }

              this.doneEvents[i].Set(); // thread done

            }, oId);
         }

         WaitHandle.WaitAll(doneEvents);

}

原文

I made this small windows service in c# and I believe I may have done something wrong with my ThreadPool code that prevents my Windows Service from completely starting. If you must know, the windows service seems to be running perfectly only that when looked upon the Services console, it still states that it is "starting". When I restarted my server, the service seem to have stopped again even though I have set it to Automatic startup.

Please see my code below:

protected override void OnStart(string[] args)
{
     int itemCount = itemList.Count;

     this.doneEvents = new ManualResetEvent[itemCount];
     for (int i = 0; i < itemCount; i++)
     {
         int oId = this.itemList[i];
         this.doneEvents[i] = new ManualResetEvent(false);

         ThreadPool.QueueUserWorkItem(data =>
         {
             while (this.activated)
             {
                 DateTime start = DateTime.Now;

                 // my code here

                 // choke point
                 TimeSpan duration = (DateTime.Now - start);
                 if (duration.Milliseconds < CONST_WAITMILLISECONDS)
                    Thread.Sleep((CONST_WAITMILLISECONDS - duration.Milliseconds));
              }

              this.doneEvents[i].Set(); // thread done

            }, oId);
         }

         WaitHandle.WaitAll(doneEvents);

}

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放手` 2024-11-21 02:13:28

您正在通过 WaitHandle.WaitAll(doneEvents); 阻止 OnStart 调用。 Windows 尝试启动该服务，但由于 WaitAll 而超时。

如果您希望 Windows 将服务视为已启动，则需要让 OnStart 完成。

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风吹短裙飘 2024-11-21 02:13:28

我认为您可以将 OnStart 内的逻辑包装在一个线程中。当您收到 OnStop 事件时，该线程将关闭。

像这样的东西：

Thread _ServiceThread;
protected override void OnStart(string[] args) { 
    _ServiceThread = new Thread(() => { /* your current OnStart logic here...*/ });
    _ServiceThread.Start();
}
protected override void OnStop() {
    _ServiceThread.Stop();
}

I think you could wrap the logic inside OnStart in a thread. This thread would be closed when you received an OnStop event.

Something like this:

Thread _ServiceThread;
protected override void OnStart(string[] args) { 
    _ServiceThread = new Thread(() => { /* your current OnStart logic here...*/ });
    _ServiceThread.Start();
}
protected override void OnStop() {
    _ServiceThread.Stop();
}

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