我可以用 R 计算 z 分数吗？
通过阅读 stackoverflow 的评论，我发现 z-score 可能是用 Python 或 perl 计算的，但我没有尚未遇到任何 R 语言。我错过了吗？用R可以完成吗？
作为（http://en.wikipedia.org/wiki/Standard_score。）
z-score = (x-μ)/σ
x is a raw score to be standardized;
μ is the mean of the population;
σ is the standard deviation of the population.
我相信有为此设计的 R 包？我们在哪里可以找到它们？或者类似的标准化包？
Possible Duplicate:
R, correlation: is there a func that converts a vector of nums to a vector of standard units
By reading stackoverflow's comments, I found z-score maybe calculated with Python or perl, but I did not comes across any for R yet. Did I miss it? Is it possible to be done with R?
As (http://en.wikipedia.org/wiki/Standard_score.)
z-score = (x-μ)/σ
x is a raw score to be standardized;
μ is the mean of the population;
σ is the standard deviation of the population.
I believe there are R packages designed for this? Where can we found them? Or similar package for normalization?
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如果
x是具有原始分数的向量，则scale(x)是具有标准化分数的向量。或手动：
(x-mean(x))/sd(x)if
xis a vector with raw scores thenscale(x)is a vector with standardized scores.Or manually:
(x-mean(x))/sd(x)