JVM 是否会内联对象的实例变量和方法？
假设我有一个非常紧密的内部循环，每次迭代都会访问和改变一个簿记对象，该对象存储一些有关算法的简单数据，并具有简单的操作逻辑
。簿记对象是私有的和最终的，并且它的所有方法都是私有的，最终和@inline。下面是一个示例（使用 Scala 语法）：
object Frobnicate {
private class DataRemaining(val start: Int, val end: Int) {
@inline private def nextChunk = ....
}
def frobnicate {
// ...
val bookkeeper = new DataRemaining(0, 1000)
while( bookeeper.hasData ) {
val data = bookkeeper.nextChunk
// ......
}
}
}
JVM 是否会将整个 DataRemaining 对象内联到 Frobnicate.frobnicate 中？也就是说，它会将 start 和 end 视为局部变量，并将 nextChunk 代码直接内联到 frobnicate 中吗？
Suppose I have a very tight inner loop, each iteration of which accesses and mutates a single bookkeeping object that stores some simple data about the algorithm and has simple logic for manipulating it
The bookkeeping object is private and final and all of its methods are private, final and @inline. Here's an example (in Scala syntax):
object Frobnicate {
private class DataRemaining(val start: Int, val end: Int) {
@inline private def nextChunk = ....
}
def frobnicate {
// ...
val bookkeeper = new DataRemaining(0, 1000)
while( bookeeper.hasData ) {
val data = bookkeeper.nextChunk
// ......
}
}
}
Will the JVM ever inline the whole DataRemaining object into Frobnicate.frobnicate? That is, will it treat start and end as local variables and inline the nextChunk code directly into frobnicate?
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在 Java 中，它可以在您所遇到的情况下内联字段和方法。它并没有完全消除对象，但已经接近了。我认为 Scala 也会以类似的方式工作。
In Java it can inline fields and methods in a situation as you have. It does not eliminate the Object completely, but gets close. I assume Scala would work similarly.