为什么此代码在 Vista 中有效，但在 7 中无效？

Question

由于某种原因，每次我让人在 Vista 中运行这个程序时，它都能完美运行，但一旦我将它转移到 Windows 7 PC，它就会停止在 ActionListener 的操作执行方法中间，这意味着我可以单击我的选择，但它永远不会说出所选尺寸。 有什么办法可以解决这个问题吗？

import java.io.*;
import java.util.*;
import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
public class SizerFrame extends JFrame {
    ButtonGroup buttons = new ButtonGroup();
    JTextField width = new JTextField(2);
    JTextField height = new JTextField(2);
    double inchesPerTimeline = 2.1;
    public SizerFrame()
    {
        super("Timeline Application");
        Dimension screen = Toolkit.getDefaultToolkit().getScreenSize();
        setBounds(screen.width/2-125,screen.height/2-90,250,180);
        getContentPane().setLayout(new GridBagLayout());
        GridBagConstraints c = new GridBagConstraints();
        int[] gridX = new int[]{0,0,0,0};
        int[] gridY = new int[]{0,1,2,3};
        int[] gridW = new int[]{1,1,2,5};
        String[] titles = new String[]{"6\"","9\"","10\"","Custom"};
        String[] actions = new String[]{"6","9","10","C"};
        for (int a = 0; a < 4; a++)
        {
            JRadioButton current = new JRadioButton(titles[a]);
            current.setActionCommand(actions[a]);
            c.gridx = gridX[a];
            c.gridy = gridY[a];
            c.gridwidth = gridW[a];
            buttons.add(current);
            getContentPane().add(current,c);
        }
        c.gridwidth = 1;
        String[] title = new String[]{"      ","Width","Height"};
        gridX = new int[]{9,10,12};
        for (int a = 0; a< 3; a++)
        {
            c.gridx = gridX[a];
            getContentPane().add(new JLabel(title[a]),c);
        }
        c.gridx = 11;
        getContentPane().add(width,c);
        c.gridx = 13;
        getContentPane().add(height,c);
        c.gridx = 11;
        c.gridy = 0;
        c.gridwidth = 2;
        JButton button = new JButton("Done");
        button.addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent e) {
                ButtonModel x = buttons.getSelection();
                String size = "XXX";
                System.out.println("Getting screen resolution");
                int screenRes = Toolkit.getDefaultToolkit().getScreenResolution();
                System.out.println("Successfully got screen resolution");
                if (x!=null)
                    size = x.getActionCommand();
                try{
                    TimeTable.width = new Integer(size)*screenRes;
                    TimeTable.height = (int)((TimeTable.titleCount+1)*inchesPerTimeline*screenRes);
                }
                catch(NumberFormatException ex)
                {
                    try{
                        TimeTable.width = (int)(new Double(width.getText().trim())*screenRes);
                        TimeTable.height = (int)(new Double(height.getText().trim())*screenRes);
                    }
                    catch (NumberFormatException except)
                    {
                        return;
                    }
                }
                TimeTable.ready = true;
                System.out.println("Size selected");
                dispose();
            }
        });
        getContentPane().add(button,c);
        addWindowListener(new WindowAdapter() {
            public void windowClosing(WindowEvent winEvt){
                System.exit(0);
            }
        });
        setVisible(true);
    }
}

简要说明： 我有一个在 Windows Vista 中用 Excel 运行的宏，我尝试将其分发到运行 Windows 7 的计算机。执行后，代码无法继续执行，即它从未打印出“Size selected”字样。该程序的其余部分从 C:\Users\?\AppData\TimeLineMacroProgram 文件夹中引入一个 csv 文件，然后在同一目录中创建一个图像。但这是当前已损坏的代码部分。每当 GUI 弹出时，我都会选择 9" 选项并单击完成，这应该将 9 作为参数传递，然后打印出“Size Selected”，但它不仅会处理窗口。请帮忙。

Answer 1

远景猜测：

如果宽度和高度文本字段没有内容，则操作侦听器会退出：在两个 NumberFormatException 后返回。这将阻止显示“已选择的尺寸”，并且不会处理该框架。如果您得到输出“成功获得屏幕分辨率”，然后它似乎停止工作，这可能就是原因。但如果您遇到这种情况，然后单击其他内容，然后单击“完成”，它将打印选定的尺寸。