如何在mongodb中进行不同和分组？

发布于 2024-11-13 07:05:07 字数 127 浏览 1 评论 0原文

如何进行 mysql 查询 SELECT COUNT(DISTINCT ip), COUNT(DISTINCT area) FROM Visit_logs GROUP BY t_hour 在 mongodb 中没有多重 MapReduce？

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固执像三岁 2024-11-20 07:05:07

您必须在对象中保留“键”列表，并将您的计数计算为不同键的计数；这可以在 MongoDb 的 map/reduce 中的 finalize 方法中完成。

像（未经测试）的东西：

var mapFn = function() {
  emit(this.t_hour, { ips: [this.ip], areas: [this.area] );
};

var reduceFn = function(key, values) {
  var ret = { ips: {}, areas: {} };
  // objects used as "sets"
  var ips = {};
  var areas = {};

  values.forEach(function(value) {
    value.ips.forEach(function(ip) {
      if (!ips[ip]) {
        ips[ip] = true; // mark as seen
        ret.ips.push(ip);
      }
    });
    value.areas.forEach(function(area) {
      if (!areas[area]) {
        areas[area] = true; // mark as seen
        ret.areas.push(area);
      }
    });
  });
};

var finalizeFn = function(key, value) {
  return { ips: value.ips.length; areas: value.areas.length };
}

You have to keep the list of "keys" in your objects, and compute your count as the count of the distinct keys; this can be done in the finalize method in MongoDb's map/reduce.

Something like (untested):

var mapFn = function() {
  emit(this.t_hour, { ips: [this.ip], areas: [this.area] );
};

var reduceFn = function(key, values) {
  var ret = { ips: {}, areas: {} };
  // objects used as "sets"
  var ips = {};
  var areas = {};

  values.forEach(function(value) {
    value.ips.forEach(function(ip) {
      if (!ips[ip]) {
        ips[ip] = true; // mark as seen
        ret.ips.push(ip);
      }
    });
    value.areas.forEach(function(area) {
      if (!areas[area]) {
        areas[area] = true; // mark as seen
        ret.areas.push(area);
      }
    });
  });
};

var finalizeFn = function(key, value) {
  return { ips: value.ips.length; areas: value.areas.length };
}

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