使用不带表单的 Django CreateView 创建对象

发布于 2024-11-13 06:47:11 字数 468 浏览 4 评论 0原文

我正在 django 1.3 中使用基于分类的视图，并试图弄清楚如何在不使用表单的情况下创建对象。我不需要任何用户输入来创建对象，但我仍然收到一条错误消息，提示模板丢失。下面是我当前的视图，我尝试对 form_valid 方法进行子类化，但它不起作用。任何帮助将不胜感激。

class ReviewerCreateView(CreateView):
    model = Reviewer

    def form_valid(self, form):
        self.object = form.save(commit=False)
        self.object.user = self.request.user
        self.object.role = 2
        self.object.save()
        return HttpResponseRedirect(self.get_success_url())

原文

I am using classed based views with django 1.3 and am trying to figure out how to create an object without using the form. I do not need any user input to create the object but I am still getting an error message that the template is missing. Below is my current view where I have tried to subclass the form_valid method but its not working. Any help would be appreciated.

class ReviewerCreateView(CreateView):
    model = Reviewer

    def form_valid(self, form):
        self.object = form.save(commit=False)
        self.object.user = self.request.user
        self.object.role = 2
        self.object.save()
        return HttpResponseRedirect(self.get_success_url())

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

一场春暖 2024-11-20 06:47:11

CreateView 是一种专用视图，其目的是在 GET 上显示表单并验证表单数据并根据 POST 上的表单数据创建新对象。

由于您不需要显示表单并处理表单数据，因此 CreateView 不适合您的工作。

您要么需要一个普通的基于函数的旧视图，或者，如果您更喜欢使用基于类的视图，请从 View 派生并覆盖 get() 或 post() 。例如，调整您的示例代码：

class ReviewerCreator(View):
    def get(self, request, *args, **kwargs):
         Reviewer(user=request.user, role=2).save()
         return HttpResponseRedirect('/your_success_url/')

A CreateView is a specialized view whose purpose is to display a form on GET and validate the form data and create a new object based on the form data on POST.

Since you don't need to display a form and process the form data, a CreateView is not the tool for your job.

You either need a plain old function-based view, or, if you prefer to use a class-based view, derive from View and override get() or post(). For example, adapting your sample code:

class ReviewerCreator(View):
    def get(self, request, *args, **kwargs):
         Reviewer(user=request.user, role=2).save()
         return HttpResponseRedirect('/your_success_url/')

回复收藏 0 原文

柳絮泡泡 2024-11-20 06:47:11

我认为如果视图不需要表单，则不需要对表单执行任何明确的操作。

您可以实例化一个 Reviewer 对象。它只是一个Python对象。

class ReviewerCreateView(CreateView):
    model = Reviewer

    self.object.user = self.request.user
    self.object.role = 2
    self.object.save()
    return HttpResponseRedirect(self.get_success_url())

I don't believe a view needs to do anything explicit with a form if it does not need one.

You can instantiate a Reviewer object. It's just a python object.

class ReviewerCreateView(CreateView):
    model = Reviewer

    self.object.user = self.request.user
    self.object.role = 2
    self.object.save()
    return HttpResponseRedirect(self.get_success_url())

回复收藏 0 原文

~没有更多了~