Cocos2D 围绕物体的贝塞尔曲线，就像通过重力一样

发布于 2024-11-13 06:09:02 字数 660 浏览 9 评论 0原文

我正在尝试操纵一个物体。当它靠近另一个物体（比如说地球仪）时，我希望地球仪对原始物体产生引力。我知道我应该使用 CCBezierTo，所以这与其说是一个编程问题，不如说是一个数学问题。

从数学上讲，我如何计算出贝塞尔曲线的三个点（1、2 和终点），并根据其距离赋予其权重（距离越远 = 拉力越小）。我已经在变量中映射了距离。

想象一下围绕月球弹弓的宇宙飞船。

代码：

ccBezierConfig bezier;
bezier.controlPoint_1 = ccp(projectile.position.x + 10, projectile.position.y + 20);
bezier.controlPoint_2 = ccp(projectile.position.x + 20, projectile.position.y + 40);
bezier.endPosition = ccp(projectile.position.x + 30, projectile.position.y+60);
id bezierAction = [CCBezierTo actionWithDuration:1 bezier:bezier];
[projectile stopAllActions];
[projectile runAction: bezierAction];

原文

I'm trying to manipulate an object. When it gets near another object, let's say a globe, I want the globe to have a gravitational pull on the original object. I know I'm supposed to use CCBezierTo, so this isn't so much a programming question as it is a math question.

Mathematically, how could I figure out the three points of the bezier curve (1, 2, and end) and give it a weight depending on its distance (further away = less pull). I already have the distance mapped out in a variable.

Think of a spaceship slingshotting around the moon.

Code:

ccBezierConfig bezier;
bezier.controlPoint_1 = ccp(projectile.position.x + 10, projectile.position.y + 20);
bezier.controlPoint_2 = ccp(projectile.position.x + 20, projectile.position.y + 40);
bezier.endPosition = ccp(projectile.position.x + 30, projectile.position.y+60);
id bezierAction = [CCBezierTo actionWithDuration:1 bezier:bezier];
[projectile stopAllActions];
[projectile runAction: bezierAction];

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