使用Python进行并行计算

发布于 2024-11-11 18:49:35 字数 426 浏览 2 评论 0原文

这是我的 python 脚本的代码：

  import time
  for j in range(1,150,1):
        for i in range(1,5,1):    
           x = j + i
           print(x)
           time.sleep(180)

该脚本是从我的有限元程序启动的，可以由 python 操作。如果我启动这个脚本，它就会开始运行，但是如果调用 time.sleep 被激活，有限元程序也会停止工作。脚本的主要任务是开始打印 5 次“x”，停止脚本一段时间，然后再次打印 5 次“x”。最终程序中使用了另一个命令，而不是“打印”。必须避免 FE 程序停止。我该如何处理？我已经尝试过不同的事情，例如线程，但这也不起作用。您的意思是可以通过使用并行进程来解决问题吗？感谢您的建议。

原文

here is the code of my python script:

  import time
  for j in range(1,150,1):
        for i in range(1,5,1):    
           x = j + i
           print(x)
           time.sleep(180)

This script is started out of my Finite Element programm which can be manipulated by python. If i start this script it starts to run, but if the call time.sleep is activated the Finite Element program also stops working. The main task of the script shall be to start print 5 times "x" stop the script for a certain time and print 5 times "x" again. Instead of "print" another command is used in the final program. The stopping of the FE program has to avoided. How can i manage that? I already tried different things, e.g. threading, but that doesn't work too. Do you mean the problem can be solved by using parallel processes?
Thanks for your suggestions.

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梦屿孤独相伴 2024-11-18 18:49:35

你打算做这样的事情吗：

#! /usr/bin/env python

import threading
import time

class Worker (threading.Thread):
    def run (self):
        for j in range(1,150,1):
            for i in range(1,5,1):
                x = j + i
                print "Worker says: %d" % x
            time.sleep (5)

if __name__ == '__main__':
    Worker ().start ()
    for i in range (1, 100):
        print "Main thread says: I am running."
        time.sleep (1)

Do you intend to do something like this:

#! /usr/bin/env python

import threading
import time

class Worker (threading.Thread):
    def run (self):
        for j in range(1,150,1):
            for i in range(1,5,1):
                x = j + i
                print "Worker says: %d" % x
            time.sleep (5)

if __name__ == '__main__':
    Worker ().start ()
    for i in range (1, 100):
        print "Main thread says: I am running."
        time.sleep (1)

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