堆、数据段、堆栈分配

发布于 2024-11-11 16:53:27 字数 329 浏览 3 评论 0原文

我正在查看以下程序，不确定内存是如何分配的以及为什么：

void function() {
    char text1[] = "SomeText";
    const char* text2 = "Some Text";
    char *text = (char*) malloc(strlen("Some Text") + 1 );
}

在上面的代码中，最后一个显然在堆中。但是，据我了解 text2 位于程序的数据段中，而 text1 可能位于堆栈上。或者我的假设是错误的？这里正确的假设是什么？这个编译器依赖吗？

原文

Am looking at the following program and not sure how the memory is allocated and why:

void function() {
    char text1[] = "SomeText";
    const char* text2 = "Some Text";
    char *text = (char*) malloc(strlen("Some Text") + 1 );
}

In the above code, the last one is obviously in the heap. However, as I understand text2 is in the data segment of the program and text1 may be on the stack. Or is my assumption wrong? What is the right assumption here? Is this compiler dependent?

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二智少女 2024-11-18 16:53:27

// Array allocated on the stack and initialized with "SomeText" string.
// It has automatic storage duration. You shouldn't care about freeing memory.
char text1[] = "SomeText"; 

// Pointer to the constant string "Some Text".
// It has static storage duration. You shouldn't care about freeing memory.
// Note that it should be "a pointer to const".
// In this case you'll be protected from accidential changing of 
// the constant data (changing constant object leads to UB).
const char* text2 = "Some Text";

// malloc will allocate memory on the heap. 
// It has dynamic storage duration. 
// You should call "free" in the end to avoid memory leak.
char *text = (char*) malloc(strlen("Some Text") + 1 );

// Array allocated on the stack and initialized with "SomeText" string.
// It has automatic storage duration. You shouldn't care about freeing memory.
char text1[] = "SomeText"; 

// Pointer to the constant string "Some Text".
// It has static storage duration. You shouldn't care about freeing memory.
// Note that it should be "a pointer to const".
// In this case you'll be protected from accidential changing of 
// the constant data (changing constant object leads to UB).
const char* text2 = "Some Text";

// malloc will allocate memory on the heap. 
// It has dynamic storage duration. 
// You should call "free" in the end to avoid memory leak.
char *text = (char*) malloc(strlen("Some Text") + 1 );

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