Ruby 排列（内置） - 结果不包含相邻的相同字母

发布于 2024-11-11 14:01:54 字数 573 浏览 4 评论 0原文

感谢您昨天的帮助，也感谢您教我一些新东西。 :)

我还有另一个基于排列的问题...我的算法有效，但是我遇到的问题是生成的列表中缺少相同的相邻字符。

例如，如果我有字符列表 az,0-9,- 假设最大长度为 2，那么我应该看到 aa、bb、cc、dd、ee、ff 等，令人恶心。

length = 1
alphabet = [('a'..'z').to_a, ('0'..'9').to_a, ('-').to_a].flatten
prefix = 'file-'
suffix = '.txt'


while length < 3


alphabet.permutation(length).each do |x|

@name =  prefix+x.join('').to_s+suffix
puts @name

end

length += 1

end

但是，我只看到以下内容：

file-ba.txt
file-bc.txt

请注意缺少的“bb”，并且这种情况会一直持续到程序完成。

我确信我错过了一些东西，只是不确定什么？

原文

Thank you for your help yesterday and for teaching me something new as well. :)

I have another question based on permutation... the algorithm I have works however I have the issue that identical adjacent characters are missing from the list generated.

For example, if I have the character list a-z,0-9,- and let's say that the maximum length is 2, then I should see aa, bb, cc, dd, ee, ff, etc. ad nauseum.

length = 1
alphabet = [('a'..'z').to_a, ('0'..'9').to_a, ('-').to_a].flatten
prefix = 'file-'
suffix = '.txt'


while length < 3


alphabet.permutation(length).each do |x|

@name =  prefix+x.join('').to_s+suffix
puts @name

end

length += 1

end

However, I am only seeing the following: