使用 JSON 更新记录时 MySQL 语法错误

Question

我主要是一名 JavaScript 人员，正在为客户端构建一个库，该库根据 HTTP_REFERRER 在 MySQL 中缓存一些数据。如果数据与服务器上的数据不同，则会更新缓存。我不知道我到底做错了什么，但它说存在语法错误：

if(mysql_query("UPDATE `cache-test` (cache) SET ('".addslashes(preg_replace('/\s\s+/', ' ', $referrer['cache']))."') WHERE url = '".$referrer['current']."'",$con)){ echo "saved"; }
else { echo mysql_error($con); }

我得到的错误是：

您的 SQL 语法有错误；检查与您的 MySQL 服务器版本相对应的手册，了解在 '(cache) SET ('[{\"LatLng\":{\"Ba\":45.531124,\"Ca\":-122.68374699999998} 附近使用的正确语法,\“InfoW”位于第 1 行

发送的数据看起来像这样（当然，在被删除和添加斜杠之前）：

[{"LatLng":{"Ba":45.531124,"Ca":-122.68374699999998},"InfoWindow":"\n        <address>1125 NW 12th Ave, Portland, OR</address>\n        <p>My first apartment</p>\n      ","originalAddress":"1125 NW 12th Ave, Portland, OR"},{"LatLng":{"Ba":45.5144501,"Ca":-122.67644239999998},"InfoWindow":"\n        <address>1230 SW 2nd Ave, Portland, OR</address>\n        <p>My 2nd apartment</p>\n      ","originalAddress":"1230 SW 2nd Ave, Portland, OR"},{"LatLng":{"Ba":45.748955,"Ca":-122.47959000000003},"InfoWindow":"\n        <address>17501 NE 188th Ct, Brush Prairie, WA</address>\n        <p>The first place I lived by my own</p>\n      ","originalAddress":"17501 NE 188th Ct, Brush Prairie, WA"},{"LatLng":{"Ba":45.756944,"Ca":-122.43575800000002},"InfoWindow":"\n        <address>18607 NE Erickson Rd, Brush Prairie, WA</address>\n        <p>Last place I lived with my parents</p>\n      ","originalAddress":"18607 NE Erickson Rd, Brush Prairie, WA"}

Answer 1

您没有要设置的字段：

UPDATE `cache-test` SET field_name = 'your huge val'

Answer 2

将 addslash 替换为：

mysql_real_escape_string()

$cache = mysql_real_escape_string(preg_replace('/\s\s+/', ' ', $referrer['cache']));

mysql_query("UPDATE `cache-test`  
            SET (cache = '$cache') 
          WHERE url = '".$referrer['current']."'",$con));