我收到了一个不存在的内容的未定义引用错误

发布于 2024-11-10 06:17:30 字数 388 浏览 3 评论 0原文

当我尝试编译此代码时

Analysis2::Analysis2() //line 13
{
    Seconds_v = 0;    //Seconds_v and Seconds_t are both of type int 
    Seconds_t = 0;    //and declared in header
}

，出现此错误

analysis2.cpp：13：对`FileParameters :: FileParameters（）'的未定义引用

为什么它给我该未定义的引用？ FileParameters 是 Analysis2 中包含的一个类，如果有帮助的话，在 Analysis2 头文件中定义了一个 FileParameters 对象。

原文

When I try to compile this code

Analysis2::Analysis2() //line 13
{
    Seconds_v = 0;    //Seconds_v and Seconds_t are both of type int 
    Seconds_t = 0;    //and declared in header
}

I get this error

analysis2.cpp:13: undefined reference to `FileParameters::FileParameters()'

Why is it giving me that undefined reference? FileParameters is a class included in Analysis2 and there is a FileParameters object defined in the Analysis2 header file if that helps.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

滥情稳全场 2024-11-17 06:17:30

当您有构造函数时，如果您没有在初始值设定项列表中显式构造每个成员变量，则每个成员变量都会自动默认构造。上面的代码自动扩展为：

Analysis2::Analysis2() : mFileParams(), Seconds_v(), Seconds_t() // line 13
{
    Seconds_v = 0;    //Seconds_v and Seconds_t are both of type int 
    Seconds_t = 0;    //and declared in header
}

如果您还没有实现 FileParameters 的默认构造函数，或者甚至没有可访问的构造函数，这就是您收到的错误。

When you have constructor, every member variable is automatically default-constructed if you don't explicitly construct it in the initializer list. Your code above automatically expands to:

Analysis2::Analysis2() : mFileParams(), Seconds_v(), Seconds_t() // line 13
{
    Seconds_v = 0;    //Seconds_v and Seconds_t are both of type int 
    Seconds_t = 0;    //and declared in header
}

And if you didn't implement the default constructor of FileParameters yet, or don't even have an accessible one, that's the error you get.

回复收藏 0 原文