如何使用 xcodebuild 构建特定的架构？
我有依赖于 32 位 指针的遗留代码，并且希望使用 xCodeBuild 从命令行构建该代码。由于某种原因这不起作用。这是我使用的命令：
xcodebuild -configuration Debug -arch i386
-workspace MyProject.xcworkspace -scheme MyLib
这是我得到的输出
[BEROR]No architectures to compile for
(ONLY_ACTIVE_ARCH=YES, active arch=x86_64, VALID_ARCHS=i386).
显然，它正在尝试构建 x86_64 代码，但由于我只从 VALID_ARCHS 启用了 i386 xCode 项目设置。
有没有办法让它明白我不需要 64 位库？
I have legacy code that relies on pointers being 32-bit and want to use xCodeBuild to build that code from command line. This doesn't work for some reason. Here's the command I use:
xcodebuild -configuration Debug -arch i386
-workspace MyProject.xcworkspace -scheme MyLib
here's the output I get
[BEROR]No architectures to compile for
(ONLY_ACTIVE_ARCH=YES, active arch=x86_64, VALID_ARCHS=i386).
Clearly it's trying to build x86_64 code and failing miserably since I only enabled i386 from VALID_ARCHS in xCode project settings.
Is there a way to make it understand I don't want a 64-bit library?
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如果您希望 xcodebuild 使用
ARCHS参数，则必须将ONLY_ACTIVE_ARCH设置为NO。通过传递这些参数，您可以强制采用正确的架构。请参阅此参考了解细节。
You have to set the
ONLY_ACTIVE_ARCHtoNOif you wantxcodebuildto use theARCHSparameters. By passing these parameters, you can force the proper architecture.See this reference for details.
仅构建活动架构(ONLY_ACTIVE_ARCH)
是- 为连接的设备构建具有单一架构的二进制文件否- 为特定构建二进制文件-arch（有效架构又名VALID_ARCHS）（如果已指定）或对于其他情况下的所有架构建议使用
Yes用于调试（以节省构建时间），No用于发布构建。注意：在模拟器上运行是安全的
要检查版本，请使用
lipo -info[关于]Build Active Architecture Only(ONLY_ACTIVE_ARCH)
YES- build binary with a single architecture for a connected deviceNO- build binary for a specific-arch(valid architecturesakaVALID_ARCHS) if it was specified or for all the architectures in other casesThe recommendation is to use
Yesfor Debug (to save on build time) andNofor Release build.Note: it is safe to run on simulator
To check the version use
lipo -info[About]