收集函数中的表单变量并将它们作为单个变量发送

Question

我有一个带有复选框的表格。提交表单时，我想收集单个变量中复选框的所有选中值，并将其与另一个变量一起发送到不同的页面。请帮忙。

<form name="form1" method="get" onsubmit="sendThis()">
<input type=checkbox name="checkbux" value=<from database/>"
<input type=checkbox name="checkbux" value=<from database/>"
<input type=checkbox name="checkbux" value=<from database/>"
<input type=checkbox name="checkbux" value=<from database/>"
<input type="submit" value="Submit">
</form>

function sendThis()
{
var tableName = "<?= $p ?>"; //obtaining the value from another php file
var allVar = a,c,d; //checked values from check boxes
window.location = 'http://localhost/fourthpage.php?q=' + allVar + '&p=' + tableName'
}

Answer 1

您无需执行 javascript 函数即可实现此目的。像这样

<form name="form1" action="/fourthpage.php" method="get">
<input type=checkbox name="q" value=<from database/>
<input type=checkbox name="q" value=<from database/>
<input type=checkbox name="q" value=<from database/>
<input type=checkbox name="q" value=<from database/>
<input type=hidden name="p" value="<?= $p ?>" />
<input type="submit" value="Submit">
</form>

Answer 2

将其发送到数组中，
例如：

<input type=checkbox name="checkbux[]" value=<from database/>"
<input type=checkbox name="checkbux[]" value=<from database/>"
<input type=checkbox name="checkbux[]" value=<from database/>"