使用打开文件对话框将位图图像加载到 Windows 窗体中

Question

我需要使用打开文件对话框在窗口窗体中打开位图图像（我将从驱动器加载它）。图像应适合图片框。

这是我尝试过的代码：

private void button1_Click(object sender, EventArgs e)
{
    var dialog = new OpenFileDialog();

    dialog.Title  = "Open Image";
    dialog.Filter = "bmp files (*.bmp)|*.bmp";

    if (dialog.ShowDialog() == DialogResult.OK)
    {                     
        var PictureBox1 = new PictureBox();                    
        PictureBox1.Image(dialog.FileName);
    }

    dialog.Dispose();
}

Answer 1

您必须创建 位图 类，使用加载图像的构造函数重载从文件中在磁盘上。现在编写代码时，您尝试使用 PictureBox.Image 属性，就像它是方法一样。

将您的代码更改为如下所示（还利用使用 语句以确保正确处理，而不是手动调用 Dispose 方法）：

private void button1_Click(object sender, EventArgs e)
{
    // Wrap the creation of the OpenFileDialog instance in a using statement,
    // rather than manually calling the Dispose method to ensure proper disposal
    using (OpenFileDialog dlg = new OpenFileDialog())
    {
        dlg.Title = "Open Image";
        dlg.Filter = "bmp files (*.bmp)|*.bmp";

        if (dlg.ShowDialog() == DialogResult.OK)
        {
            PictureBox PictureBox1 = new PictureBox();

            // Create a new Bitmap object from the picture file on disk,
            // and assign that to the PictureBox.Image property
            PictureBox1.Image = new Bitmap(dlg.FileName);
        }
    }
}

当然，这不会在表单上的任何位置显示图像，因为您拥有的图片框控件创建的内容尚未添加到表单中。您需要将刚刚创建的新图片框控件添加到表单的 Controls 集合 使用 添加方法。请注意此处添加到上述代码的行：

private void button1_Click(object sender, EventArgs e)
{
    using (OpenFileDialog dlg = new OpenFileDialog())
    {
        dlg.Title = "Open Image";
        dlg.Filter = "bmp files (*.bmp)|*.bmp";

        if (dlg.ShowDialog() == DialogResult.OK)
        {
            PictureBox PictureBox1 = new PictureBox();
            PictureBox1.Image = new Bitmap(dlg.FileName);

            // Add the new control to its parent's controls collection
            this.Controls.Add(PictureBox1);
        }
    }
}

Answer 2

工作正常。
试试这个，

private void addImageButton_Click(object sender, EventArgs e)
{
    OpenFileDialog of = new OpenFileDialog();
    //For any other formats
    of.Filter = "Image Files (*.bmp;*.jpg;*.jpeg,*.png)|*.BMP;*.JPG;*.JPEG;*.PNG"; 
    if (of.ShowDialog() == DialogResult.OK)
    {
        pictureBox1.ImageLocation = of.FileName;

    }
}

Answer 3

您应该尝试：

• 在表单中直观地创建图片框（更容易）
• 将图片框的 Dock 属性设置为 Fill （如果您希望图像填充表单）
• 设置 SizeMode 的图片框到 StretchImage

最后：

private void button1_Click(object sender, EventArgs e)
{
    OpenFileDialog dlg = new OpenFileDialog();
    dlg.Title = "Open Image";
    dlg.Filter = "bmp files (*.bmp)|*.bmp";
    if (dlg.ShowDialog() == DialogResult.OK)
    {                     
        PictureBox1.Image = Image.FromFile(dlg.Filename);
    }
    dlg.Dispose();
}

Answer 4

private void button1_Click(object sender, EventArgs e)
{
    OpenFileDialog open = new OpenFileDialog();
    if (open.ShowDialog() == DialogResult.OK)
        pictureBox1.Image = Bitmap.FromFile(open.FileName);
}

Answer 5

您也可以尝试这样， PictureBox1.Image = Image.FromFile("" 或

);

Answer 6

PictureBox.Image 是一个属性，而不是一个方法。你可以这样设置：

PictureBox1.Image = System.Drawing.Image.FromFile(dlg.FileName);

Answer 7

您可以尝试以下操作：

private void button1_Click(object sender, EventArgs e)
    {
        OpenFileDialog fDialog = new OpenFileDialog();
        fDialog.Title = "Select file to be upload";
        fDialog.Filter = "All Files|*.*";
        //  fDialog.Filter = "PDF Files|*.pdf";
        if (fDialog.ShowDialog() == DialogResult.OK)
        {
            textBox1.Text = fDialog.FileName.ToString();
        }
    }

Answer 8

这很简单。只需添加：

PictureBox1.BackgroundImageLayout = ImageLayout.Zoom;