触发器不更新sql

发布于 2024-11-09 16:53:04 字数 311 浏览 0 评论 0原文

尽管此操作在完成时已成功完成，但并未具有所需的更新。

CREATE TRIGGER Trigger1
On dbo.[table1] 
FOR UPDATE
AS
Declare @Id int;
SELECT @Id = Issue_Id FROM dbo.[table1]

INSERT INTO dbo.[storage]
    SELECT Id, Title, project, Problem
    FROM dbo.[table2]
    WHERE Id = @Id

我做错了什么或者我不能在触发器范围内使用变量吗？

非常感谢

原文

Although this is completed successfully on completion, it is not having the desired update.

CREATE TRIGGER Trigger1
On dbo.[table1] 
FOR UPDATE
AS
Declare @Id int;
SELECT @Id = Issue_Id FROM dbo.[table1]

INSERT INTO dbo.[storage]
    SELECT Id, Title, project, Problem
    FROM dbo.[table2]
    WHERE Id = @Id

Is there something I am doing wrong or that I can't use variables within the scope of a trigger?

Many thanks

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庆幸我还是我 2024-11-16 16:53:04

支持多行更新

CREATE TRIGGER Trigger1 On dbo.[table1] FOR UPDATE
AS
SET NOCOUNT ON

INSERT INTO dbo.[storage]
    SELECT t.Id, t.Title, t.project, t.Problem
    FROM dbo.[table2] t
        JOIN INSERTED I ON t.ID = I.ID
GO

如果 table2 实际上是 table1 （这更有意义：table1 与 storage 和 table2 有何关系？）...

CREATE TRIGGER Trigger1 On dbo.[table1] FOR UPDATE
AS
SET NOCOUNT ON

INSERT INTO dbo.[storage]
    SELECT Id, Title, project, Problem
    FROM INSERTED
GO

To support multirow updates

CREATE TRIGGER Trigger1 On dbo.[table1] FOR UPDATE
AS
SET NOCOUNT ON

INSERT INTO dbo.[storage]
    SELECT t.Id, t.Title, t.project, t.Problem
    FROM dbo.[table2] t
        JOIN INSERTED I ON t.ID = I.ID
GO

If table2 is actually table1 (which makes more sense: how is table1 related to storage and table2?)...

CREATE TRIGGER Trigger1 On dbo.[table1] FOR UPDATE
AS
SET NOCOUNT ON

INSERT INTO dbo.[storage]
    SELECT Id, Title, project, Problem
    FROM INSERTED
GO

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呆° 2024-11-16 16:53:04

要一次性处理多个更新和inserted表：

CREATE TRIGGER Trigger1
On dbo.[table1] 
FOR UPDATE
AS

INSERT INTO dbo.[storage]
    SELECT Id, Title, project, Problem
    FROM dbo.[table2] t2
         JOIN Inserted i ON i.Issue_ID = t2.Id

To handle multple updates and the inserted table in one go:

CREATE TRIGGER Trigger1
On dbo.[table1] 
FOR UPDATE
AS

INSERT INTO dbo.[storage]
    SELECT Id, Title, project, Problem
    FROM dbo.[table2] t2
         JOIN Inserted i ON i.Issue_ID = t2.Id

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夜雨飘雪 2024-11-16 16:53:04

请仔细阅读以下建议。

而不是下面的行，

SELECT @Id = Issue_Id FROM dbo.[table1]

它必须是下面的。

SELECT Issue_Id FROM Inserted

以下是更新后的内容。

CREATE TRIGGER Trigger1
On dbo.[table1] 
FOR UPDATE
AS
SET NOCOUNT ON
Declare @Id int;

With CTE as 
(
    SELECT Issue_Id FROM Inserted I
    Inner Join [table1] T on T.Issue_Id  = I.Issue_Id
)

INSERT INTO dbo.[storage]
SELECT Id, Title, project, Problem
FROM dbo.[table2]
Inner Join CTE c on c.Issue_Id = Id

有关详细信息

在 SQL Server 中，正在插入/修改或删除的记录占用 DML 触发器中可用的两个临时表中。这些表被插入和删除。 INSERTED 表已插入或更新记录。 DELETED 表具有正在更新或删除的记录的旧状态。

Please go through the below suggestion.

Instead of the below line

SELECT @Id = Issue_Id FROM dbo.[table1]

It had to be following.

SELECT Issue_Id FROM Inserted

Following is the updated one.

CREATE TRIGGER Trigger1
On dbo.[table1] 
FOR UPDATE
AS
SET NOCOUNT ON
Declare @Id int;

With CTE as 
(
    SELECT Issue_Id FROM Inserted I
    Inner Join [table1] T on T.Issue_Id  = I.Issue_Id
)

INSERT INTO dbo.[storage]
SELECT Id, Title, project, Problem
FROM dbo.[table2]
Inner Join CTE c on c.Issue_Id = Id

For more information

In SQL server the records which are being inserted / modified or deleted occupies themselves in two temporary tables available in a DML trigger. These tables are INSERTED and DELETED. The INSERTED table has inserted or updated records. The DELETED table has the old state of the records being updated or deleted.

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