Grails - 渲染模型和变量
通过控制器向 GSP 提供模型并提供变量的正确方法是什么？我有一个不属于模型的一部分，但也需要由 GSP 渲染。
我从什么开始：
def index = {
render controller:"test", action:"index", model:[user:user]
}
举个例子——我认为我是如何修改它的（错误的）
def index = {
def url = "http://www.stackoverflow.com"
render controller:"test", action:"index", model:[user:user, testvar: url]
}
What is the correct way to give a model to a GSP via the controller but also supply a variable. I have one that is not part of the model, but also needs to be rendered by the GSP.
What I started with:
def index = {
render controller:"test", action:"index", model:[user:user]
}
For an example - how I modified it (incorrectly) I think
def index = {
def url = "http://www.stackoverflow.com"
render controller:"test", action:"index", model:[user:user, testvar: url]
}
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在您的示例中，您应该能够编写如下内容：
默认情况下，Grails 视图将自动从相关操作获取变量返回。这是通过映射视图路径 - 控制器/操作名称自动完成的。
如果你调用“渲染”，那就有点不同了。您可以渲染任何可能与您的控制器/操作无关的视图。我建议仅在需要时使用它。
In your example, you should be able to write things like this:
By default, Grails view will automatically get the variable returns from the relevant action. This is done automatically by mapping view path - controller/action name.
If you call "render", it's a bit different. You can render any view which may not associated to your controller/action. I recommend only using it when in need.
你的代码看起来是正确的。这会将模型中的 var 发送到 gsp，但如果您想像在
remoteFunction中那样将其发送到 javascript，则需要使用grails.converters.JSON如下：Your code looks right. That will send the var in the model to the gsp, but if you want to send it to the javascript as in a
remoteFunction, you need to usegrails.converters.JSONas next: