如何删除已释放的子视图
初学者的问题：我试图在将子视图添加到视图然后释放它之后将其删除，即我有：
for (int i = 0; i < 9, i++) {
UIButton *btn = [indexButtons objectAtIndex:i];
btn.tag = x;
[notePage1 addSubview:btn];
[btn release];
}
如何摆脱这些 btn 之一，例如数字 0？我想到
UIButton *btn = [indexButtons objectAtIndex:0];
if ([btn isDescendantOfView:notePage1]) { [btn removeFromSuperview]; }
[btn release];
但这只会使应用程序崩溃。我根本没有收到错误日志？ - 应用程序简单地终止。我该如何正确地做到这一点？
A beginner's question: I am trying to remove a subview after having added it to a view and then releasing it, i.e. I have:
for (int i = 0; i < 9, i++) {
UIButton *btn = [indexButtons objectAtIndex:i];
btn.tag = x;
[notePage1 addSubview:btn];
[btn release];
}
How can I get rid of one of these btn, e.g. number 0? I thought of
UIButton *btn = [indexButtons objectAtIndex:0];
if ([btn isDescendantOfView:notePage1]) { [btn removeFromSuperview]; }
[btn release];
But this will simply crash the app. I get no error log at all? - app simply terminates. How do I do this properly?
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评论（3）
您不应该释放该按钮，因为您没有分配它。
这都是关于对象所有权的。你永远不应该释放一个不属于你的对象。您可以通过发送以下消息之一来获取对象的所有权：
You shouldn't release the button, because you didn't allocate it.
It's all about object ownership. You should never release an object that you don't own. You can take ownership of an object by sending one of the following messages:
您不应该释放任何这些片段中的按钮。仅当您专门使用了
retain、alloc、copy或new时才使用release>。您的代码应该是：
添加
到超级视图会自动增加保留计数并自动删除发布。您不必担心这些。
You shouldn't release the button in any of these snippets. You only use
releaseif you have specifically usedretain,alloc,copyornew.Your code should be:
and
Adding to a to a superview increases the retain count automatically and removing releases automatically. You don't have to worry about any of it.
不要释放按钮，你从未分配过它们
don't release buttons, you never Alloc'ed them