如何编写自定义约束来检查类中至少一个布尔字段是否为 true

发布于 2024-11-09 14:14:28 字数 494 浏览 5 评论 0原文

我有一个名为“Scheduler”的类，它有 7 个布尔字段。我想在休眠中编写一个约束来检查至少一个布尔字段是否为真。

这是“调度程序”类。

public class Scheduler {

private String description;

@NotNull
private Boolean sMondays;

@NotNull
private Boolean sTuesdays;

@NotNull
private Boolean sWednesdays;

@NotNull
private Boolean sThursdays;

@NotNull
private Boolean sFridays;

@NotNull
private Boolean sSaturdays;

@NotNull
private Boolean sSundays;

public Scheduler() {

}
}

谁能帮我写一下提到的约束。

谢谢！！！！！！！！！

原文

I have a class called "Scheduler" which has 7 Boolean fields. I want to write a constraint in hibernate to check that at-least one boolean field is true.

Here is the "Scheduler" class.

public class Scheduler {

private String description;

@NotNull
private Boolean sMondays;

@NotNull
private Boolean sTuesdays;

@NotNull
private Boolean sWednesdays;

@NotNull
private Boolean sThursdays;

@NotNull
private Boolean sFridays;

@NotNull
private Boolean sSaturdays;

@NotNull
private Boolean sSundays;

public Scheduler() {

}
}

Can anyone please help me in writing the mentioned constraint.

Thanks!!!!!!!!!

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冷心人i 2024-11-16 14:14:28

这很复杂，因为您使用的是布尔值而不是原始布尔值，这会产生空指针异常的风险。

为了简化逻辑，我将修改每个字段声明以将其初始化为 false。当您将它们注释为 @NotNull 时，我的假设是这将适用于您现有的业务逻辑。

如果您这样做，则可以使用 || 轻松验证至少一个为真：

public boolean validateAtLeastOneIsTrue() {
    return getsMondays() || getsTuesdays() || getsWednesdays()
    || getsThursdays() || getsFridays() || getsSaturdays()
    || getsSundays();
}

This is complicated because you're using Booleans instead of the primitive boolean, which creates the risk of null pointer exceptions.

To simplify the logic, I'd modify each field declaration to initialize it to false. As you've annotated them as @NotNull, my assumption is this will work with your existing business logic.

If you do this, your validation for at least one is true is quite simply achieved using ||:

public boolean validateAtLeastOneIsTrue() {
    return getsMondays() || getsTuesdays() || getsWednesdays()
    || getsThursdays() || getsFridays() || getsSaturdays()
    || getsSundays();
}

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