快速 Jbutton 单击导致无任何操作

发布于 2024-11-09 12:15:17 字数 3375 浏览 3 评论 0原文

嘿伙计们，我一直在编写的代码有问题。

我有一个包含两个按钮的 JFrame。每个按钮都有一个操作。我遇到的问题是一个名为 "btnDone" 的 JButton ，它应该返回到上一个屏幕。如果我继续重复按下按钮，最终 "btnDone" 将停止执行它应该执行的逻辑。我的代码如下：

对于框架：

public class ItemLocatorPnl extends JPnl
{
    private static final long serialVersionUID = 1L;
    private Pnl pnl;
    private JButton btnDone;
    private JButton btnRefreshData;

    public void setPnl(Pnl pnl) {
        this.pnl = pnl;
    }

    public ItemLocatorPnl(Pnl pnl)
    {
        super();

        this.pnl=pnl;
        initialize();   
    }


    private void initialize()
    {
        this.setSize(300, 200);

        JPanel jContentPane = new JPanel();
        jContentPane.setLayout(new MigLayout());

        // (1) Remove window frame
        setUndecorated(true);


        // (3) Set background to white
        jContentPane.setBackground(Color.white);


        // (5) Add components to the JPnl's contentPane
        POSLoggers.initLog.writeDebug("ItemLocator: Adding icon");
        jContentPane.add(wmIconLabel, "align left");
        POSLoggers.initLog.writeDebug("ItemLocator: Adding global controls");
        jContentPane.add(createUpperPanel(), "align right, wrap");
        POSLoggers.initLog.writeDebug("ItemLocator: Adding main panel");
        jContentPane.add(pnl,"width 100%,height 100%, span 3");

        // (6) Attach the content pane to the JPnl
        this.setContentPane(jContentPane);

    }

    private JPanel createUpperPanel()
    {
        JPanel upperPanel=new JPanel();


        MigLayout mig = new MigLayout("align right", "", "");
        upperPanel.setLayout(mig);
        upperPanel.setBackground(Color.WHITE);


        // Create the Done button
        btnDone= GraphicalUtilities.getPOSButton("<html><center>Done</center></html>");
        btnDone.addActionListener(new ButtonListener());

        // Create the Refresh Data button
        btnRefreshData = GraphicalUtilities.getPOSButton("<html><center>Refresh<br>Data</center></html>");
        btnRefreshData.addActionListener(new ButtonListener()); 

        //Addiing buttons to the Panel
        upperPanel.add(btnRefreshData, "width 100:170:200, height 100!");
        upperPanel.add(btnDone, "width 100:170:200, height 100!");

        return upperPanel;

    }

    public class ButtonListener implements ActionListener {

        public void actionPerformed(ActionEvent e) {

            try {
                if (e.getSource() == btnRefreshData) {

                    Actual.refreshData();
                } else if (e.getSource() == btnDone) {
                    Actual.backToMainScreen();

                }
            }
            catch (Exception ex)
            {

            }
        }

    }

}

这是单击时 btnDone 按钮调用的方法：

public static void backToMainScreen()
{

    frame.setVisible(false);
    frame.dispose();
}

这是显示 JFrame 的代码：

public static void displayItemLocatorFrame()
{
    pnl = new Pnl();
    frame = new Frame(pnl);

    frame.setVisible(true);
    pnl.getSearchCriteria().requestFocus();

}

请注意“ Frame”对象是静态的，我的所有方法都是静态的，它们存在于名为 Actual 的静态类中。

简而言之，我只是想确保无论用户单击按钮多少次，无论单击的速度有多快，框架都应该正常运行。有什么建议吗？（我尝试同步我的方法，但没有成功..）

原文

Hey guys, I have a problem with a code that I've been writing.

I have a JFrame that contains two buttons. Each of these buttons has an action. The problem I'm having is with a JButton called "btnDone" that's supposed to get back to a previous screen. If I I keep pushing the button repeatedly, eventually the "btnDone" would stop doing the logic it's supposed to do. My code is as follows:

For the frame:

public class ItemLocatorPnl extends JPnl
{
    private static final long serialVersionUID = 1L;
    private Pnl pnl;
    private JButton btnDone;
    private JButton btnRefreshData;

    public void setPnl(Pnl pnl) {
        this.pnl = pnl;
    }

    public ItemLocatorPnl(Pnl pnl)
    {
        super();

        this.pnl=pnl;
        initialize();   
    }


    private void initialize()
    {
        this.setSize(300, 200);

        JPanel jContentPane = new JPanel();
        jContentPane.setLayout(new MigLayout());

        // (1) Remove window frame
        setUndecorated(true);


        // (3) Set background to white
        jContentPane.setBackground(Color.white);


        // (5) Add components to the JPnl's contentPane
        POSLoggers.initLog.writeDebug("ItemLocator: Adding icon");
        jContentPane.add(wmIconLabel, "align left");
        POSLoggers.initLog.writeDebug("ItemLocator: Adding global controls");
        jContentPane.add(createUpperPanel(), "align right, wrap");
        POSLoggers.initLog.writeDebug("ItemLocator: Adding main panel");
        jContentPane.add(pnl,"width 100%,height 100%, span 3");

        // (6) Attach the content pane to the JPnl
        this.setContentPane(jContentPane);

    }

    private JPanel createUpperPanel()
    {
        JPanel upperPanel=new JPanel();


        MigLayout mig = new MigLayout("align right", "", "");
        upperPanel.setLayout(mig);
        upperPanel.setBackground(Color.WHITE);


        // Create the Done button
        btnDone= GraphicalUtilities.getPOSButton("<html><center>Done</center></html>");
        btnDone.addActionListener(new ButtonListener());

        // Create the Refresh Data button
        btnRefreshData = GraphicalUtilities.getPOSButton("<html><center>Refresh<br>Data</center></html>");
        btnRefreshData.addActionListener(new ButtonListener()); 

        //Addiing buttons to the Panel
        upperPanel.add(btnRefreshData, "width 100:170:200, height 100!");
        upperPanel.add(btnDone, "width 100:170:200, height 100!");

        return upperPanel;

    }

    public class ButtonListener implements ActionListener {

        public void actionPerformed(ActionEvent e) {

            try {
                if (e.getSource() == btnRefreshData) {

                    Actual.refreshData();
                } else if (e.getSource() == btnDone) {
                    Actual.backToMainScreen();

                }
            }
            catch (Exception ex)
            {

            }
        }

    }

}

This is the method that the btnDone button calls upon clicking:

public static void backToMainScreen()
{

    frame.setVisible(false);
    frame.dispose();
}

This is the code that displays the JFrame:

public static void displayItemLocatorFrame()
{
    pnl = new Pnl();
    frame = new Frame(pnl);

    frame.setVisible(true);
    pnl.getSearchCriteria().requestFocus();

}

Please note that the "frame" object is static, and all of my methods are static, and they exist in a static class called Actual.

So in short, I just want to make sure that no matter how many times a user clicks on the button, and no matter how fast the clicks were, the frame should act normally.
Any suggestions? (I tried synchronizing my methods with no luck..)

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谁的年少不轻狂 2024-11-16 12:15:17

我通常更喜欢使用 Action你想做什么。

因此，您的代码可能如下所示：

btnDone = new JButton(new CloseFrameAction());

...

private class CloseFrameAction extends AbstractAction
{
    public CloseFrameAction()
    {
         super("Done");
    }

    public void actionPerformed(ActionEvent e) 
    {
        frame.dispose();
        setEnabled(false);
    }
}

注意 setEnabled(false) 行 - 这应该禁用按钮并防止用户再次单击它。显然我不知道您的确切要求是什么，但这是我会采取的一般方法。

I would generally prefer to use an Action for what you're trying to do.

So your code might look like this:

btnDone = new JButton(new CloseFrameAction());

...

private class CloseFrameAction extends AbstractAction
{
    public CloseFrameAction()
    {
         super("Done");
    }

    public void actionPerformed(ActionEvent e) 
    {
        frame.dispose();
        setEnabled(false);
    }
}

Notice the setEnabled(false) line - this should disable the button and prevent the user clicking on it again. Obviously I don't know what your exact requirements are but this is the general approach I would take.

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