Java 中使用 HashMap 的 ArrayList 实现字符串相等？我正在使用 .equals()
我正在尝试从 HashMap 列表中删除项目，并且在查看控制台输出时，很明显被比较的字符串是相等的，并且我正在使用 .equals(String x) 方法进行比较，但是输出的这个不断显示错误，并且没有任何内容从列表中删除。谁能给我一个提示，告诉我我在这里做错了什么？
public void removeWord(String wd) {
Log.println(Log.INFO, "Initial Size", "Initial size" + String.valueOf(allWords.size()));
for (int x = 0; x < allWords.size(); x++) {
Log.println(Log.INFO, "Current Word", allWords.get(x).get("Long") + " " + wd);
Log.println(Log.INFO, "Equality?", String.valueOf(allWords.get(x).get("Long").toUpperCase().equals(wd)));
if (allWords.get(x).get("Long").toUpperCase().equals(wd)) {
allWords.remove(x);
Log.println(Log.INFO, "Removed something", "Removed Something!!!!");
clearAdapter();
}
}
Log.println(Log.INFO, "Size of list", "Size of list" + String.valueOf(allWords.size()));
}
I'm trying to remove items from a List of HashMaps, and when looking at the console output, it's plainly clear that the strings being compared are equal, and I am using the .equals(String x) method to compare, however the output of this continually shows false, and nothing gets removed from the list. Could anyone give me a hint as to what I'm doing wrong here?
public void removeWord(String wd) {
Log.println(Log.INFO, "Initial Size", "Initial size" + String.valueOf(allWords.size()));
for (int x = 0; x < allWords.size(); x++) {
Log.println(Log.INFO, "Current Word", allWords.get(x).get("Long") + " " + wd);
Log.println(Log.INFO, "Equality?", String.valueOf(allWords.get(x).get("Long").toUpperCase().equals(wd)));
if (allWords.get(x).get("Long").toUpperCase().equals(wd)) {
allWords.remove(x);
Log.println(Log.INFO, "Removed something", "Removed Something!!!!");
clearAdapter();
}
}
Log.println(Log.INFO, "Size of list", "Size of list" + String.valueOf(allWords.size()));
}
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您正在将映射到
"Long"的字符串的大写值与wd的原始值进行比较。除非wd以大写形式传入，否则您可能会失败。尝试使用 < code>equalsIgnoreCase 并通过调用修剪< /a>.我希望这有帮助！You are comparing the uppercase value of the String mapped to
"Long"to the original value ofwd. Unlesswdis being passed in as uppercase you could be off. Try usingequalsIgnoreCaseand also make sure that both strings don't have leading or trailing spaces by callingtrim. I hope that helps!当您解决问题时，这可能是由字符串或值中的无关不可见字符引起的 - 也尝试比较日志中的长度 - 您应该使用迭代器来遍历所有单词和迭代器的删除方法，否则您可能会得到一个迭代不一致。
When you solve the problem, which may be caused by extraneous invisible characters in the string or the values - try comparing lengths in your logs as well - you should use an iterator to go over allwords and the iterator's remove method, or you may get an inconsistent iteration.