MySQL:使用 JOIN 和 GROUP_CONCAT 进行更新

发布于 2024-11-09 09:17:28 字数 343 浏览 0 评论 0原文

这可能吗?

我有 2 个表,客户表和订单表。现在我想在“客户”中的一列中填写该客户的所有订单 ID(以逗号分隔)。

我尝试了类似的方法,但它不起作用:

UPDATE customers AS c
LEFT JOIN orders AS o ON o.customerid=c.customerid
SET c.orders = GROUP_CONCAT(DISTINCT o.orderid)

我得到“组函数的无效使用”。

附言。我知道最好始终在 SELECT/JOIN 中动态获取 GROUP_CONCAT 值,但我只是想知道是否可以以某种方式填充此列。

Is this possible?

I have 2 tables, Customers and Orders. Now I want to fill a column in Customers with all order id's of that customer (comma separated).

I tried something like this, but it doesnt work:

UPDATE customers AS c
LEFT JOIN orders AS o ON o.customerid=c.customerid
SET c.orders = GROUP_CONCAT(DISTINCT o.orderid)

I get 'Invalid use of group function'.

PS. I know it's better to always dynamically get the GROUP_CONCAT values in a SELECT/JOIN, but I'm just wondering if I can fill this column in some way.

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评论(4

临走之时 2024-11-16 09:17:28

您需要在 group_concat 中添加 order by,如下例所示

注意:group_concat(version ORDER BY version SEPARATOR ',')

UPDATE 
items i,
(SELECT pduid, group_concat(version ORDER BY version SEPARATOR ',') AS 'versions'
     from items GROUP BY pduid) AS version_lookup
SET i.versions = version_lookup.versions
WHERE version_lookup.pduid = i.pduid

You will need to add an order by in the group_concat as shown in the example below

Note: group_concat(version ORDER BY version SEPARATOR ',')

UPDATE 
items i,
(SELECT pduid, group_concat(version ORDER BY version SEPARATOR ',') AS 'versions'
     from items GROUP BY pduid) AS version_lookup
SET i.versions = version_lookup.versions
WHERE version_lookup.pduid = i.pduid
彼岸花似海 2024-11-16 09:17:28

这里给出的答案都不适合我,可能是因为我的情况更复杂(我需要多个连接),所以我使用了 Dennis 的解决方案,但将其拆分为一个临时表:

CREATE TEMPORARY TABLE version_lookup
SELECT pduid, group_concat(version ORDER BY version SEPARATOR ',') AS 'versions'
     from items GROUP BY pduid;

UPDATE 
items i, version_lookup
SET i.versions = version_lookup.versions
WHERE version_lookup.pduid = i.pduid;

None of the given answers here were working for me, possibly because my case was more complicated (I needed more than one join), so I used Dennis' solution but split it into a temporary table:

CREATE TEMPORARY TABLE version_lookup
SELECT pduid, group_concat(version ORDER BY version SEPARATOR ',') AS 'versions'
     from items GROUP BY pduid;

UPDATE 
items i, version_lookup
SET i.versions = version_lookup.versions
WHERE version_lookup.pduid = i.pduid;
不羁少年 2024-11-16 09:17:28

基本上,您不应该以这种方式使用 GROUP_CONCAT 函数,这不是完成工作的正确方法。

在这种情况下,您可以使用嵌套查询方法,而不是尝试使用下面指定的 JOIN,尝试此查询,希望这应该可以正确完成您的工作。

UPDATE customers AS c
SET c.orders = 
(SELECT GROUP_CONCAT(DISTINCT o.orderid) 
 FROM orders AS o 
 WHERE o.customerid = c.customerid 
 GROUP BY o.customerid);

尝试一次此查询,然后让我知道您是否还遇到任何问题。

湿婆

Basically you should not use the GROUP_CONCAT function in this manner, that's not the right way of making your work done.

In this scenario you can use nested queries approach instead of trying with JOINs as I specified below, try this query, hopefully this should do your work correctly.

UPDATE customers AS c
SET c.orders = 
(SELECT GROUP_CONCAT(DISTINCT o.orderid) 
 FROM orders AS o 
 WHERE o.customerid = c.customerid 
 GROUP BY o.customerid);

Try this query once and then let me know if you are facing any more issues.

Siva

述情 2024-11-16 09:17:28

您忘记告诉 GROUP BY 子句。

UPDATE customers AS c
LEFT JOIN orders AS o ON o.customerid=c.customerid
SET c.orders = GROUP_CONCAT(DISTINCT o.orderid)
GROUP BY o.customerid

You forget to tell the GROUP BY clause.

UPDATE customers AS c
LEFT JOIN orders AS o ON o.customerid=c.customerid
SET c.orders = GROUP_CONCAT(DISTINCT o.orderid)
GROUP BY o.customerid
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