通过测试访问数据库时，我得到 play.exceptions.JPAException: The JPA context is notinitialized

Question

我正在尝试使用 PlayFremwork 通过类访问数据库并编写测试

import static org.junit.Assert.*;
import javax.persistence.EntityManager;
import models.com.vlist.entity.classes.Playlist;
import org.junit.Test;
import play.db.jpa.JPA;
import play.db.jpa.Transactional;
import play.jobs.OnApplicationStart;
import play.mvc.Scope.Session;
public class PlaylistTest {
@Test
    @Transactional
    public void insertIntoPlaylist() {
        Playlist playlist = new Playlist();
        playlist.setId(1);
        playlist.setName("test");

        EntityManager em = JPA.em();
        em.persist(playlist);
    }
}

错误堆栈跟踪是：

    play.exceptions.JPAException: The JPA context is not initialized. JPA Entity Manager automatically start when one or more classes annotated with the @javax.persistence.Entity annotation are found in the application.
        at play.db.jpa.JPA.get(JPA.java:22)
        at play.db.jpa.JPA.em(JPA.java:51)
        at PlaylistTest.insertIntoPlaylist(PlaylistTest.java:23)
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
        at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
        at java.lang.reflect.Method.invoke(Method.java:597)
        at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
        at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
        at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
        at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
        at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:76)
        at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:50)
        at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193)
        at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52)
        at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191)
        at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42)
        at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184)
        at org.junit.runners.ParentRunner.run(ParentRunner.java:236)
        at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:49)
        at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
        at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
        at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
        at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
        at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)  

如何在编写测试时解决此问题？

谢谢你

修复了！通过扩展功能测试

public class PlaylistTest extends FunctionalTest {

    @Test
    @Transactional
    public void insertIntoPlaylist() {
        Playlist playlist = new Playlist();
        playlist.setName("new_playlist_again");

        EntityManager em = JPA.em();
        em.persist(playlist);
    }
}

Answer 1

public class PlaylistTest extends FunctionalTest {

    @Test
    @Transactional
    public void insertIntoPlaylist() {
        Playlist playlist = new Playlist();
        playlist.setName("new_playlist_again");

        EntityManager em = JPA.em();
        em.persist(playlist);
    }
}