C#启动进程参数传递数据
尝试将文件中的数据作为 C# 中的命令行参数传递并遇到问题，
ProcessStartInfo startInfo1 = new ProcessStartInfo();
startInfo1.FileName = @"myexe.exe";
startInfo1.UseShellExecute = false;
startInfo1.RedirectStandardOutput = true;
startInfo1.WindowStyle = ProcessWindowStyle.Hidden;
startInfo1.WorkingDirectory = @"C:\myfolder\";
startInfo1.Arguments = "-cmd1 x -cmd2 y < c:\\yesfile.txt";
问题在于 <; c:\yesfile.txt ...
当我调试并获取 .Arguments 并从命令行执行时，工作正常。从代码运行，我到处
Invalid command line parameters: <
搜索，我找不到从代码执行此操作（传入数据）的方法。我调用的 exe 不会将“y”作为命令行参数，因此我必须从文件中传递它才能像这样自动运行它。
更新：如何获取std输入并传入ay（基于答案） - 确保您RedirectStandardInput = true;
StreamWriter inputWriter = myProcess.StandardInput;
inputWriter.Write("y");
inputWriter.Flush();
inputWriter.Close();
trying to pass in data from a file as a cmd line argument in c# and running into issues
ProcessStartInfo startInfo1 = new ProcessStartInfo();
startInfo1.FileName = @"myexe.exe";
startInfo1.UseShellExecute = false;
startInfo1.RedirectStandardOutput = true;
startInfo1.WindowStyle = ProcessWindowStyle.Hidden;
startInfo1.WorkingDirectory = @"C:\myfolder\";
startInfo1.Arguments = "-cmd1 x -cmd2 y < c:\\yesfile.txt";
the issue is with the < c:\yesfile.txt ...
when I debug and grab the .Arguments and execute from cmd line, works fine. running from code, i get
Invalid command line parameters: <
searching around, I cant find the way to do this (pass in data) from code. The exe I am calling doesn't take in the "y" as a cmd line arg so I have to pass it in from a file to run it automatically like this.
Update: how to get the std input and pass in a y (based on answer) - make sure you RedirectStandardInput = true; as well
StreamWriter inputWriter = myProcess.StandardInput;
inputWriter.Write("y");
inputWriter.Flush();
inputWriter.Close();
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这是因为重定向
<、>等是由 shell 而不是 Windows 处理的 - 您不能从 Process.Start 使用它们。您可以改为播种
Process.StandardInput，流中包含“y”和标志startInfo1.RedirectStandardInput = true;That's because the redirections
<,>etc. are handled by the shell and not by Windows - you can't use them from Process.Start.You could instead seed your
Process.StandardInputwith a stream containing a 'y' and flagstartInfo1.RedirectStandardInput = true;