ASP.NET MVC 3 多个模型到单个表单

Question

我正在学习 ASP.NET MVC 3 并尝试创建一个具有单个表单的视图，该表单由通过外键链接在一起的多个模型组成。最终目标是将单个表单插入到所有数据库表中。

问题是，我无法弄清楚为什么当我右键单击创建视图时，表单没有在 cshtml 文件中自动生成。自动生成的代码很有帮助，因为我有许多链接在一起的表，以及必须验证和插入的许多字段。如果无法自动生成表单，那么最有效/最优雅的方法是什么？

这是我所拥有的内容的简化。

型号：

class Customer
{
    [Key]
    public UInt64 CustomerId { get; set; }

    [Required(ErrorMessage = "Name is required.")]
    [Display(Name = "Customer Name")]
    [MaxLength(50)]
    public string FullName { get; set; }
}

class CustomerAdditionalDetails1
{
    [ForeignKey("Customer")]
    public UInt64 CustomerId { get; set; }

    [Required(ErrorMessage = "This info is required.")]
    [Display(Name = "Customer Information")]
    [MaxLength(50)]
    public string SomeInfo { get; set; }
}

class CustomerAdditionalDetails2
{  // same foreign key as CustomerAddtionalDetails1, but with different properties
}

class CustomerAdditionalDetails3
{  // same foreign key as CustomerAddtionalDetails1, but with different properties
}

...

public class CustomerModel
{
    public Customer Customer { get; set; }
    public CustomerAdditionalDetails1 CustomerAdditionalDetails1 { get; set; }
    public CustomerAdditionalDetails2 CustomerAdditionalDetails2 { get; set; }
    public CustomerAdditionalDetails3 CustomerAdditionalDetails3 { get; set; }
    ...
}

控制器：

public ActionResult Submit()
{
    return View();
}

[HttpPost]
public ActionResult Submit(CustomerModel customer)
{
    return View();
}

请帮忙！

Answer 1

当您生成视图时，您是否基于 CustomerModel 创建强类型视图？如果您生成视图，则不会在页面中输出任何值，因为您的所有属性都是对其他对象的引用。您需要模型中包含实际值类型，以便脚手架将它们自动包含在视图中。也就是说，您始终可以按照下面的示例自行将它们添加到视图中。

我还注意到在您的控制器中，您的 GET 方法不会将模型返回到要渲染的视图。如果您想基于模型生成视图，那么您需要传递您希望为其生成视图的对象。

@model MvcApplication3.Models.CustomerModel

@{
    ViewBag.Title = "Index";
}

<h2>Index</h2>

<fieldset>
    <legend>CustomerModel</legend>
</fieldset>
<ul>
<li>@Model.Customer.FullName</li>
<li>@Model.CustomerAdditionalDetails1.SomeInfo1</li>
<li>@Model.CustomerAdditionalDetails2.SomeInfo2</li>
</ul>
<p>
    @Html.ActionLink("Edit", "Edit", new { /* id=Model.PrimaryKey */ }) |
    @Html.ActionLink("Back to List", "Index")
</p>


public class CustomerController : Controller
    {
        public ActionResult Index()
        {
            CustomerModel customerModel = new CustomerModel() 
            { 
                Customer = new Customer()
                {
                    FullName = "Dan"
                },
                CustomerAdditionalDetails1 = new CustomerAdditionalDetails1() 
                { 
                    SomeInfo1 = "Somewhere1" 
                },
                CustomerAdditionalDetails2 = new CustomerAdditionalDetails2()
                {
                    SomeInfo2 = "Somewhere2"
                },
                CustomerAdditionalDetails3 = new CustomerAdditionalDetails3()
                {
                    SomeInfo3 = "Somewhere3"
                }
            };

            return View(customerModel);
        }
    }