如何在FUSE中建立符号链接？

发布于 2024-11-09 07:46:44 字数 1250 浏览 5 评论 0原文

我正在开发一个 FUSE 应用程序，它采用一个包含 mp3 的目录，并在另一个具有以下结构的目录中安装文件系统（根据其标签）：

    Artist1
       |
       -----> Album11
                 |
                 -----> Track01
                 -----> Track02
                 -----> Track03
                 -----> Track04
                 -----> Track05
       -----> Album12
       ....
    Artist2
       |
       -----> Album21
       -----> Album22
       ....
    Artist3
    .....

我正在使用 sqlite3 数据库来维护到真实文件的链接。艺术家和专辑元素是文件夹，曲目元素是指向真实元素的链接。

我已经成功地为艺术家和专辑创建了文件夹。但现在我有一个问题。

我有这个：

  static int getattr(...) {

      ....
      else if ( level == 0  || level == 1 || level == 2 )
      {
          // Estamos en el primer nivel. Son artistas, y por lo tanto, carpetas.
          stbuf->st_mode = S_IFDIR | 0755;
          stbuf->st_nlink = 2;
          lstat(path, stbuf);
      }
      else if (level == 3) {
      // Estamos en el tercer nivel. Son canciones, por lo que son enlaces
      stbuf->st_mode = S_IFLNK | 0755;
      stbuf->st_nlink = 2;
      lstat(path, stbuf);
      }

      .....
  }

现在，当我进入曲目目录时，您会收到一条消息，告诉我该功能未实现（链接功能）。我必须实现哪个函数才能知道链接指向哪里？或者我必须在哪里填充指针的方向？

谢谢！

原文

I'm developing a FUSE app that takes a directory with mp3's and mounts a filesystem in another directory with the following structure (according to their tag's):

    Artist1
       |
       -----> Album11
                 |
                 -----> Track01
                 -----> Track02
                 -----> Track03
                 -----> Track04
                 -----> Track05
       -----> Album12
       ....
    Artist2
       |
       -----> Album21
       -----> Album22
       ....
    Artist3
    .....

I'm using a sqlite3 database to mantain the links to the real files. The artists and albums elements are folders, and the tracks elements are links to the real ones.

I have achieved to create the folders for the artists and the albums. But now I have a problem.

I have this:

  static int getattr(...) {

      ....
      else if ( level == 0  || level == 1 || level == 2 )
      {
          // Estamos en el primer nivel. Son artistas, y por lo tanto, carpetas.
          stbuf->st_mode = S_IFDIR | 0755;
          stbuf->st_nlink = 2;
          lstat(path, stbuf);
      }
      else if (level == 3) {
      // Estamos en el tercer nivel. Son canciones, por lo que son enlaces
      stbuf->st_mode = S_IFLNK | 0755;
      stbuf->st_nlink = 2;
      lstat(path, stbuf);
      }

      .....
  }

And now, When I ls in the tracks directory y get a message that tells me that the function is not implemented (the links functions). Which function do I have to implement to know where the link points? Or where do I have to fill the direction of the pointer?

Thanks!

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北凤男飞 2024-11-16 07:46:44

这似乎对我有用：

添加一个int my_readlink(const char *path, char *buf, size_t size)函数，您的struct fusion_operations成员.readlink 应该指向。对于符号链接路径，您的函数应使用一个以零结尾的字符串填充缓冲区 buf，该字符串是链接目标的路径。不要写入超过 size 字节。例如，做类似的事情：
```
strncpy(buf, "/目标/路径", 大小);
```
在您的 my_getattr() 函数中（其中 struct fusion_operations 成员.getattr 应该指向），对于符号链接路径，在第二个参数中设置（struct stat * stbuf ）：
stbuf->st_mod 到 S_IFLNK |第0777章 stbuf->st_nlink 到 1 stbuf->st_size 为目标路径的长度（长度中不包括字符串的零终止符）

This seems to work for me:

Add a int my_readlink(const char *path, char *buf, size_t size) function, which your struct fuse_operations member .readlink should point to. For the symbolic link path, your function should fill the buffer buf with a zero-terminated string which is the path of the link target. Don't write more than size bytes. E.g. do something like:
```
strncpy(buf, "/target/path", size);
```
In your my_getattr() function (which struct fuse_operations member .getattr should point to), for the symbolic link path, set in the 2nd parameter (struct stat * stbuf):
- stbuf->st_mod to S_IFLNK | 0777
- stbuf->st_nlink to 1
- stbuf->st_size to the length of the target path (don't include the string's zero terminator in the length)