由于多重对象引用而导致的java垃圾收集
car_object_1 能够进行垃圾收集吗？有人坚持认为，由于 car_object_1 有两个引用，因此它永远不会被车库收集。这是真的吗？
Car createACar()
{
Car c = new MyCar(); //car_object_1 was created
return c;
}
void use_the_car()
{
Car c2 = createACar();
c2.run();
}
Will the car_object_1 be able to garbage collected? Somebody maintain that as car_object_1 has two reference so it will never be garaged collected. Is it true?
Car createACar()
{
Car c = new MyCar(); //car_object_1 was created
return c;
}
void use_the_car()
{
Car c2 = createACar();
c2.run();
}
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不，他们在胡说八道。假设
run()中没有任何内容将引用隐藏在某处，则在use_the_carc2.run(); 语句之后，汽车有资格进行垃圾回收代码>.Java不引用计数 - 即使循环引用也不是问题（例如，
Car和Driver相互引用，但没有任何内容涉及到他们中的任何一个）。也许与你交谈的人正在考虑稍微不同的情况？
No, they're talking nonsense. Assuming there's nothing within
run()which stashes a reference somewhere, the car is eligible for garbage collection after thec2.run();statement inuse_the_car.Java is not reference counted - even circular references aren't a problem (e.g. where a
Carand aDriverhave a reference to each other, but nothing has a reference to either of them).Perhaps the person you were talking to was thinking of a slightly different situation?